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# How many diagonals does a regular 11 -sided polygon contain?

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Math Expert
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How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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23 Nov 2016, 05:57
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45% (medium)

Question Stats:

56% (01:17) correct 44% (01:25) wrong based on 421 sessions

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How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

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Posts: 4340
Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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23 Nov 2016, 06:14
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Top Contributor
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Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

A nice/fast approach that doesn't involve any counting techniques is to recognize that, for each of the 11 points (vertices), there are 8 possible points that we can connect to to create a diagonal.

ASIDE: there are 8 possible points because we cannot create a diagonal by connecting 2 adjacent points.
So, there are 8 possible diagonals for each of the 11 points
These means that there are 88 possible diagonals in total (8x11=88).
However, we need to recognize that this method counts each diagonal twice. For example, it counts the diagonal AB and the diagonal BA as 2 separate diagonals.

So, to account for this duplication, we'll divide 88 by 2 to get 44

Cheers,
Brent
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How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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23 Nov 2016, 09:09
9
6
11-sided polygon contains 11 vertices which can be joined with each other in 11C2 ways=55 ways.
But this includes the sides of the polygon also, hence subtracting 11, gives 44.
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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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23 Nov 2016, 10:21
5
4
Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

No of Diagonals of a Polygon = $$\frac{n(n - 3)}{2}$$

No of Diagonals of a Polygon = $$\frac{11(11 - 3)}{2}$$

No of Diagonals of a Polygon = $$44$$

Hence, answer will be (D) 44

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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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28 Nov 2016, 05:48
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1
Its D i.e. 44

The formula for the number of diagonals for an n sided polygon is represented as nC2-n
where n represents the number of sides of the polygon

Here, n=11
so by placing the value of n we get the number of diagonals as 44
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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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02 Dec 2016, 05:56
2
Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

Given a vertex, in order to form a diagonal, we need to choose a vertex other than the vertex itself and the two adjacent vertices; thus, we have 8 possibilities for a diagonal from any given vertex. This idea is true for all 11 vertices; however, we must divide out the overlap since each diagonal is counted twice.

Thus, the number of diagonals created from an 11-sided polygon is (11 x 8) / 2 = 44 diagonals.

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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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02 Dec 2016, 06:24
No. of diagonals of a regular n sided polygon is nc2-n

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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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03 Mar 2018, 22:12
1
Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

Approach 1: Excluding the side lengths from the total line segments = nc2 - n

Approach 2: Every vertex can yield n-3 diagonals (excluding itself and two adjacent points). So, n vertices would yield n(n-3) diagonals. However, it has double counting since the diagonal from A to B is essentially the same as that from B to A. Hence, no. of unique diagonals n(n-3)/2
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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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04 Jul 2018, 00:17
Simply use this formula: n(n-3)/2 = 11*(11-3)/2 = 44
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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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18 Jul 2018, 05:51
Here we see that in the polygon containing 11 angles, the angle B have only 8 diagonals in RED ( 2 closest sides plus 1 itself are ignored).
We see that the angle C also has 8 diagonals because there is no overlap. However, we also see that overlap begins when we draw diagonals from the angle A (in the blue color).
Therefore, visually and logically we can conclude that to count the number of diagonals without counting any overlap, we will have the following:
8+8+7+6+5+4+3+2+1=44
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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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06 Nov 2018, 11:23
Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

11c2 - 11 or 11(11-3)/2

11*10/2 = 55 - 11 = 44

11 * 8/2 = 11*4 = 44

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Re: How many diagonals does a regular 11 -sided polygon contain?  [#permalink]

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01 Dec 2019, 16:39
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Re: How many diagonals does a regular 11 -sided polygon contain?   [#permalink] 01 Dec 2019, 16:39
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