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How many diagonals does a regular 11 -sided polygon contain?

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How many diagonals does a regular 11 -sided polygon contain? [#permalink]

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23 Nov 2016, 06:57
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How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55
[Reveal] Spoiler: OA

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Re: How many diagonals does a regular 11 -sided polygon contain? [#permalink]

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23 Nov 2016, 07:14
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Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

A nice/fast approach that doesn't involve any counting techniques is to recognize that, for each of the 11 points (vertices), there are 8 possible points that we can connect to to create a diagonal.

ASIDE: there are 8 possible points because we cannot create a diagonal by connecting 2 adjacent points.
So, there are 8 possible diagonals for each of the 11 points
These means that there are 88 possible diagonals in total (8x11=88).
However, we need to recognize that this method counts each diagonal twice. For example, it counts the diagonal AB and the diagonal BA as 2 separate diagonals.

So, to account for this duplication, we'll divide 88 by 2 to get 44
Answer:
[Reveal] Spoiler:
D

Cheers,
Brent
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Re: How many diagonals does a regular 11 -sided polygon contain? [#permalink]

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23 Nov 2016, 10:09
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11-sided polygon contains 11 vertices which can be joined with each other in 11C2 ways=55 ways.
But this includes the sides of the polygon also, hence subtracting 11, gives 44.
Answer D.

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Re: How many diagonals does a regular 11 -sided polygon contain? [#permalink]

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23 Nov 2016, 11:21
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Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

No of Diagonals of a Polygon = $$\frac{n(n - 3)}{2}$$

No of Diagonals of a Polygon = $$\frac{11(11 - 3)}{2}$$

No of Diagonals of a Polygon = $$44$$

Hence, answer will be (D) 44

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Re: How many diagonals does a regular 11 -sided polygon contain? [#permalink]

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28 Nov 2016, 06:48
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Straight 15 second answer!!!!!!!!!!!!!!!!!
Its D i.e. 44

The formula for the number of diagonals for an n sided polygon is represented as nC2-n
where n represents the number of sides of the polygon

Here, n=11
so by placing the value of n we get the number of diagonals as 44
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Re: How many diagonals does a regular 11 -sided polygon contain? [#permalink]

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02 Dec 2016, 06:56
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Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

Given a vertex, in order to form a diagonal, we need to choose a vertex other than the vertex itself and the two adjacent vertices; thus, we have 8 possibilities for a diagonal from any given vertex. This idea is true for all 11 vertices; however, we must divide out the overlap since each diagonal is counted twice.

Thus, the number of diagonals created from an 11-sided polygon is (11 x 8) / 2 = 44 diagonals.

Answer: D
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Re: How many diagonals does a regular 11 -sided polygon contain? [#permalink]

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02 Dec 2016, 07:24
No. of diagonals of a regular n sided polygon is nc2-n

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Re: How many diagonals does a regular 11 -sided polygon contain? [#permalink]

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03 Mar 2018, 23:12
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Bunuel wrote:
How many diagonals does a regular 11-sided polygon contain?

A. 35

B. 38

C. 40

D. 44

E. 55

Approach 1: Excluding the side lengths from the total line segments = nc2 - n

Approach 2: Every vertex can yield n-3 diagonals (excluding itself and two adjacent points). So, n vertices would yield n(n-3) diagonals. However, it has double counting since the diagonal from A to B is essentially the same as that from B to A. Hence, no. of unique diagonals n(n-3)/2
Re: How many diagonals does a regular 11 -sided polygon contain?   [#permalink] 03 Mar 2018, 23:12
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How many diagonals does a regular 11 -sided polygon contain?

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