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03 Apr 2017, 00:23
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
68% (00:49) correct
32%
(00:53)
wrong
based on 216
sessions
History
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How many different arrangements of letters are possible, if three letters are chosen without replacement from the letters A, B, C, D, and E to make the arrangement?
A. 120
B. 60
C. 20
D. 10
E. 6
A. 120
B. 60
C. 20
D. 10
E. 6
0akshay0
Joined: 19 Apr 2016
Last visit: 14 Jul 2019
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Location: India
Schools: Jindal '20 Kelley '20 Broad '20 Carey '20 Mays '20
GMAT 1: 570 Q48 V22
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Schools: Jindal '20 Kelley '20 Broad '20 Carey '20 Mays '20
GMAT 2: 640 Q49 V28
Posts: 203
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584
03 Apr 2017, 03:18
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Bunuel
How many different arrangements of letters are possible, if three letters are chosen without replacement from the letters A, B, C, D, and E to make the arrangement?
A. 120
B. 60
C. 20
D. 10
E. 6
A. 120
B. 60
C. 20
D. 10
E. 6
three letters are chosen without replacement from the letters A, B, C, D, and E in 5C3 ways = 10
these 3 letter thus selected can be arranged in 3P3 ways = 3! = 6
different arrangements of letters possible = 6*10 = 60
IMO option B is correct
Hit Kudos if you liked it
03 Apr 2017, 12:16
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Another approach:
5P3 = 5!(5-3!) = 60
Answer B
5P3 = 5!(5-3!) = 60
Answer B
