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13 Apr 2005, 08:00
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How many different arrangements of the digits 1, 2, 3, 4, and 5 are possible where no two consecutive digits are adjacent?
(A) 42
(B) 21
(C) 16
(D) 10
(E) 6
Alleged answer is B. Thanks in advance.
(A) 42
(B) 21
(C) 16
(D) 10
(E) 6
Alleged answer is B. Thanks in advance.
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13 Apr 2005, 12:00
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I tried doing it non-linearly, meaning consectuive numbers cannot be next to each other (12... and 21... are not allowed). I came up with 10 different arrangements. So, I'm assuming the question asks for arrangements where the #s are not in consecutive order themselves (i.e., 21... would be allowed, but 12... would not). Also, I assumed, that the question was asking for combinations of a set of 5 items only. So, with these added constrains, can you tell what the answer would be?
