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16 May 2018, 04:49
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
72% (00:54) correct
28%
(00:57)
wrong
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How many five-digit numbers can be formed using the digits 5, 6, 7, 8, 9, 0 if no digits can be repeated
(A) 64
(B) 120
(C) 240
(D) 600
(E) 720
(A) 64
(B) 120
(C) 240
(D) 600
(E) 720
16 May 2018, 04:58
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Solution
Given:
• 5-digit numbers needs to be formed using the digits 5, 6, 7, 8, 9, and 0
• Repetition of digits not allowed
To find:
• How many such numbers can be formed
Approach and Working:
We can find the possible cases by taking the number of options for each place.
Considering the left-most digit as the 1st digit and right-most digit as the 5th or last digit,
• No of ways 1st place can be filled = 5 [except 0]
• No of ways 2nd place can be filled = 5 [all number except the 1st digit]
• No of ways 3rd place can be filled = 4 [all number except the 1st two digits]
• No of ways 4th place can be filled = 3 [all number except the 1st three digits]
• No of ways 5th place can be filled = 2 [all number except the 1st four digits]
Hence the total number of possible cases = \(5*5*4*3*2\) = 600
Hence, the correct answer is option D.
Answer: D
18 May 2018, 11:17
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Bunuel
How many five-digit numbers can be formed using the digits 5, 6, 7, 8, 9, 0 if no digits can be repeated
(A) 64
(B) 120
(C) 240
(D) 600
(E) 720
(A) 64
(B) 120
(C) 240
(D) 600
(E) 720
Since the first digit can’t be 0, there are 5 choices for the first digit. Since the second digit can’t be repeated (but it can be 0), there are also 5 choices for the second digit. There are 4 choices for the third digit, 3 for the fourth and 2 for the fifth. Therefore, there are 5 x 5 x 4 x 3 x 2 = 600 five-digit numbers possible.
Answer: D
