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Difficulty:
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Question Stats:
68% (01:24) correct
32%
(01:30)
wrong
based on 108
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How many girls are members of both the Diving Team and the Swim Team?
(1) At a joint meeting of the Diving and Swim Teams, no members were absent and 18 girls were present.
(2) The Diving Team has 27 members, one-third of whom are girls, and the Swim Team has 24 members, half of whom are girls.
(1) At a joint meeting of the Diving and Swim Teams, no members were absent and 18 girls were present.
(2) The Diving Team has 27 members, one-third of whom are girls, and the Swim Team has 24 members, half of whom are girls.
11 Nov 2025, 06:26
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Here is my $0.02.
Right away the formula I am thinking of using is: Total = Diving + Swim - Both. We want Both = Diving + Swim - Total
(1) This tells us the total = 18. But this doesn't tell us anything about the # in diving, swimming, or both. So clearly we can come up with many different cases to arrive at a total of 18. Insufficient.
(2) This tells me that Diving = (1/3)*27 = 9, and Swim = (1/2)*24 = 12. This still doesn't tell me the number who were in both. For example, it could be that ALL girls that were in Diving could be in Swimming, in which case the total would be 12 and the answer would be 9. It could also be that none of the girls that were in Diving were in Swim. This means both = 0 and total = 21. Insufficient.
Combining (1) and (2) we get that total = 18, Dive = 9, Swim = 12 -> So Both = 9 + 12 - 8 = 3. This is a unique solution and hence SUFFICIENT.
C
Right away the formula I am thinking of using is: Total = Diving + Swim - Both. We want Both = Diving + Swim - Total
(1) This tells us the total = 18. But this doesn't tell us anything about the # in diving, swimming, or both. So clearly we can come up with many different cases to arrive at a total of 18. Insufficient.
(2) This tells me that Diving = (1/3)*27 = 9, and Swim = (1/2)*24 = 12. This still doesn't tell me the number who were in both. For example, it could be that ALL girls that were in Diving could be in Swimming, in which case the total would be 12 and the answer would be 9. It could also be that none of the girls that were in Diving were in Swim. This means both = 0 and total = 21. Insufficient.
Combining (1) and (2) we get that total = 18, Dive = 9, Swim = 12 -> So Both = 9 + 12 - 8 = 3. This is a unique solution and hence SUFFICIENT.
C
11 Nov 2025, 11:00
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How many girls are members of both the Diving Team and the Swim Team?
(1) At a joint meeting of the Diving and Swim Teams, no members were absent and 18 girls were present.
DG+SG-Both=18
Insufficient
(2) The Diving Team has 27 members, one-third of whom are girls, and the Swim Team has 24 members, half of whom are girls.
DG=(1/3)*27=9
SG=(1/2)*24=12
DG+SG-Both= ?
12+9-Both=x
Insufficient
(1)&(2)
12+9-Both=18
Both common= 12+9-18=3
Sufficient
C
(1) At a joint meeting of the Diving and Swim Teams, no members were absent and 18 girls were present.
DG+SG-Both=18
Insufficient
(2) The Diving Team has 27 members, one-third of whom are girls, and the Swim Team has 24 members, half of whom are girls.
DG=(1/3)*27=9
SG=(1/2)*24=12
DG+SG-Both= ?
12+9-Both=x
Insufficient
(1)&(2)
12+9-Both=18
Both common= 12+9-18=3
Sufficient
C
