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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
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IMO is D 9 values.
Starting from 1 to the left side of number line.
X(X+2)(X+4)(X+6)<200

Putting 2 as x, LHS will be 384>200(wrong)
Put x=1;105<200
Similarly putting x=0,-1,-2,-3,-4.....up to -7
All will give value less than 200
So Answer should be 9

Other way to do this is to put x=-6 in equation. You will get zero. So we know value of x from 1 to -6 is definitely less than 200
We just have to check for -7.

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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
1
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9

Steps:

first check with +6 as thats the greatest integer - not possible

Then check with -6 - possible, -7 is also possible.

0 to -7 is possible - 8 integers including +1

So totally 9 integers.
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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
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How many integer values of x satisfy: x(x + 2)(x + 4)(x + 6) < 200?

Let y=x+3

(y-3)(y-1)(y+1)(y+3) < 200
(y^2-9)(y^2-1) - 200 < 0
y^4 - 10y^2 - 191 < 0
(y^2-5)^2 < 216

-√216 < y^2-5 < √216, where √216 = ~15
-15 < y^2-5 < 15
-10 < y^2 < 20
---> 0 <= y^2 < 20, where y^2 must be non-negative
---> y = -4,-3,-2,-1, 0, 1, 2, 3, 4 (9 values)

Since y=x+3 and x is an integer, x also has 9 values: -7,-6,..., 0, 1

FINAL ANSWER IS (D)

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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
1
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How many integer values of x satisfy x(x+2)(x+4)(x+6)<200 ?

A. 6
B. 7
C. 8
D. 9
E. 10

x(x+2)(x+4)(x+6)<200

With four integers each 2 more than the previous multiplying, max. value of x is 1.
x = 1, 1*3*5*7 = 105 < 200
x = 2, 2*4*6*8 = 384 < 200

Similarly, x will have other negative integer values including '0'.
Values till x = -6 satisfy
x = -7, -7*-5*-3*-1 = 105 < 200
x = -8, -8*-6*-4*-2 = 384 < 200

Total values of x = 1-(-7) + 1 = 9

Answer D.
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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
1
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Quote:
How many integer values of x satisfy x(x+2)(x+4)(x+6)<200?

A. 6
B. 7
C. 8
D. 9
E. 10


x(x+2)(x+4)(x+6)<200
x=1: 1.3.5.7=35.3=105
x=2: 2.4.6.8=64.6=360+24>200
x=-7: 7.5.3.1=105
x=-8: 8.6.4.2=384>200
-8<x<2: 1--7=8+1=9

ans (D)
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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
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IMO D

x(x+2)(x+4)(x+6)<200

P= x(x+2)(x+4)(x+6) = Product of 4 consecutive number differing by 2

x= 2 , P= 2*4*6*8 > 200

x=1, P=1*3*5*7 <200
........
x= -7 , P = -7*-5*-3*-1 <200

x=-8 , P= -8*-6*-4*-2 >200

Total values of x = [-7, 1] = 9

D. 9
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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
substitute for values of x we get
that given relation is satisfied at x = -7,-6,-5,-4,-3,-2,-1,0,1,
total 9 values of x
OPTION D


How many integer values of x satisfy x(x+2)(x+4)(x+6)<200?

A. 6
B. 7
C. 8
D. 9
E. 10
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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
Bunuel wrote:

Competition Mode Question



How many integer values of x satisfy \(x(x + 2)(x + 4)(x + 6) < 200\)?

A. 6
B. 7
C. 8
D. 9
E. 10


Are You Up For the Challenge: 700 Level Questions


Asked: How many integer values of x satisfy \(x(x + 2)(x + 4)(x + 6) < 200\)?

if x =1; 1*3*5*7 = 105 < 200
If x =2; 2*4*6*8 = 2^4*4! = 16*24 = 384 > 200
If x=0; 0 < 200
If x=-1; -1*1*3*5 = - 15 < 200
..
..
If x=-7; -7*-5*-3*-1 = 105<200
x = {1,0,-1,-2,-3,-4,-5,-6,-7}; 9 solutions

IMO D
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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
Expert Reply
Bunuel wrote:

Competition Mode Question



How many integer values of x satisfy \(x(x + 2)(x + 4)(x + 6) < 200\)?

A. 6
B. 7
C. 8
D. 9
E. 10



If x is 0, -2, -4, or -6, we see that the value of the expression on the left hand side of the expression will be 0 and thus less than 200.

If x is -1, then one factor (the first one) is negative while the other three factors are positive. Therefore, the value of the expression is negative and less than 200. Similarly, if x is -5, then one factor (the last one) is positive while the other three factors are negative. Therefore, the value of the expression is negative and less than 200.

If x is -3, then the first two factors are negative and the last two are positive. Therefore, the value of the expression is positive. It might or might not be less than 200, so we have to check:

-3(-1)(1)(3) = 9 < 200 → Yes!

If x is greater than 0, then all the factors are positive. Therefore,the value of the expression is positive. It might or might not be less than 200, again we have to check:

x = 1: 1(3)(5)(7) = 105 < 200 → Yes!

x = 2: 2(4)(6)(8) = 8(48) < 200 → No!

We see that we don’t need to check any integer values greater than 2 since the value of the expression is already greater than 200 when x = 2. Last but not least, if x is less than -6, then all the factors are negative. Therefore,the value of the expression is positive. It might or might not be less than 200, so we have to check:

x = -7: -7(-5)(-3)(-1) = 105 < 200 → Yes!

x = -8: -8(-6)(-4)(-2) = 48(8) < 200 → No!

Again, we see that we don’t need to check any integer values greater than -8 since the value of the expression is already greater than 200 when x = -8. Therefore, there are 9 integer values (-7 to 1, inclusive) that satisfy the given inequality.

Answer: D
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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
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Re: How many integer values of x satisfy x(x + 2)(x + 4)(x + 6) < 200? [#permalink]
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