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12 Sep 2025, 00:16
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
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Question Stats:
55% (01:32) correct
45%
(01:48)
wrong
based on 133
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How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed?
A. 375
B. 376
C. 499
D. 500
E. 501
A. 375
B. 376
C. 499
D. 500
E. 501
12 Sep 2025, 00:45
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We can fill thousands place is 3 ways by using 1,2,3 and all other digits' place in 5 ways each.
Total numbers = 3*5*5*5 = 375
But we will also have 4000 as we will numbers not greater than 4000
Total numbers possible = 375 +1 = 376
(B) is the answer
Total numbers = 3*5*5*5 = 375
But we will also have 4000 as we will numbers not greater than 4000
Total numbers possible = 375 +1 = 376
(B) is the answer
12 Sep 2025, 09:33
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We need to find all 4 digit integers which can be formed with 0,1,2,3,4 which are greater than 999, that is from 1000 to not greater than 4000 (Which is including 4000)
1000s digit have 3 possibilities-->1,2 and 3 (Since 0 ad 4 are not possible)
100s digit have 5 possibilities(0,1,2,3,4,)--> since repetition is allowed
10s digit have 5 possibilities--> since repetition is allowed
1s digit have 5 possibilities--> since repetition is allowed
Total possibilities: (3*5*5*5)+1(4000)=375+1=376
1000s digit have 3 possibilities-->1,2 and 3 (Since 0 ad 4 are not possible)
100s digit have 5 possibilities(0,1,2,3,4,)--> since repetition is allowed
10s digit have 5 possibilities--> since repetition is allowed
1s digit have 5 possibilities--> since repetition is allowed
Total possibilities: (3*5*5*5)+1(4000)=375+1=376
