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Praetorian
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Since your number is between 10000 and 40000 first number we can select in 3 ways (1,2,3) the rest in 8 ways each ( without 7 and 4) which is ultimately 3x8x8x8x8
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BG
Since your number is between 10000 and 40000 first number we can select in 3 ways (1,2,3) the rest in 8 ways each ( without 7 and 4) which is ultimately 3x8x8x8x8



Wanna check your solution?

hint : the last digit can be only 5 or 0.

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BG
is it 3072?


well ,3072/3 would be your "current" solution.

i am worried about your criteria for divisiblity ...

every third # divisible by 15??

are you sure it works for all the #'s

thanks
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Q1.
Total No's are 3*8*8*8*2. For divisibility by 15, the Nos are
10,005, 10020, 10035 ... etc; so these are 15 appart. In this seris there will be no numbers with 7 or 4 as the digits. so we have 30,000/15 = 2,000 numbers.

It seesm that the first part about digits is redundant information. Is this solution correct. :roll:
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345XX as a pair XX can occupy 4 places in 3 of them we have 42 possibilities when is at the beginning only 36 possibilities( without 0)3x42=126+36=162 different numbers, when separate 12 ways of ordering the two numbers but in 6 of them it can not be 0 or 6x36+6x42=216+252=468, total 162+468=630 numbers.. :)
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praetorian123 could you please post the correct Ans.
Thanks



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