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Swanand
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Swanand
Thanks Bunuel. I will ensure compliance from now on :)

I agree with your approach. Can you please clarify what is wrong with the following technique?

1st digit can be chosen in 5 ways (0,1,3,4,5). This can also be 0
2nd digit can be chosen in 4 ways
.
.
Last digit can be chosen in 1 way.
Thanks

5!=120. Now, this # excludes some 4-digit numbers.

Consider this: when you have 0 as the first digit (so when you have a 4-digit number), you can have only 4-digit numbers with 1, 3, 4, and 5, thus excluding 4-digit numbers with 0. For example, 1034, 1035, 3450, ...

Hope it's clear.
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Got it! :-D Thanks.

Any general approach for solving these kind of problems?

For example,

Using digits 5,6,0,7,9 how many numbers greater than 1000 can be created? (This I have just created off hand. So there is no OA)
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Got it! :-D Thanks.

Any general approach for solving these kind of problems?

For example,

Using digits 5,6,0,7,9 how many numbers greater than 1000 can be created? (This I have just created off hand. So there is no OA)

General approach would be logic and common sense...

You can find many similar questions here: search.php?search_id=tag&tag_id=52
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