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B
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Difficulty:
55%
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Question Stats:
68% (02:24) correct
32%
(02:18)
wrong
based on 186
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How many numbers greater than a thousand can be made using the following digits without repetition: 1, 0, 3, 4, and 5:
A. 96^2
B. 96*2
C. 576
D. 24^2
E. 24*96
Evidently, a simple 5! leaves out some combinations. I am not sure which ones. Thanks
A. 96^2
B. 96*2
C. 576
D. 24^2
E. 24*96
Evidently, a simple 5! leaves out some combinations. I am not sure which ones. Thanks
26 Jun 2013, 23:38
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Swanand
We have 5 digits: {0, 1, 3, 4, 5}
We can have 4-digit OR 5-digit numbers greater than 1,000.
# of 4-digit numbers greater than 1,000 = 4*4*3*2 = 96. The first digit can take 4 values: 1, 3, 4, or 5. So, any value but 0, since in this case a number will no longer be a 4-digit and becomes 3-digit. The second digit can take 4 values (5 values minus 1 we already used for the first digit), ...
# of 5-digit numbers greater than 1,000 = 4*4*3*2*1 = 96.
Total: 96+96=2*96.
Answer: B.
Hope it's clear.
P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to the rule #3. Thank you.
26 Jun 2013, 23:46
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Thanks Bunuel. I will ensure compliance from now on 
I agree with your approach. Can you please clarify what is wrong with the following technique?
1st digit can be chosen in 5 ways (0,1,3,4,5). This can also be 0
2nd digit can be chosen in 4 ways
.
.
Last digit can be chosen in 1 way.
Thanks
I agree with your approach. Can you please clarify what is wrong with the following technique?
1st digit can be chosen in 5 ways (0,1,3,4,5). This can also be 0
2nd digit can be chosen in 4 ways
.
.
Last digit can be chosen in 1 way.
Thanks
Thanks.
