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How many ordered pairs of positive integers (x,y) satisfy the inequality 2x + 3y < 10 ?
A. One
B. Two
C. Three
D. Four
E. Five
A. One
B. Two
C. Three
D. Four
E. Five
Updated on: 20 Nov 2018, 05:00
Originally posted by Archit3110 on 19 Nov 2018, 02:58.
Last edited by Archit3110 on 20 Nov 2018, 05:00, edited 1 time in total.
Last edited by Archit3110 on 20 Nov 2018, 05:00, edited 1 time in total.
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Bunuel
How many ordered pairs of positive integers (x,y) satisfy the inequality 2x + 3y < 10 ?
A. One
B. Two
C. Three
D. Four
E. Five
A. One
B. Two
C. Three
D. Four
E. Five
2x + 3y < 10 would hold true for values of + ve integers at , (1,1), ( 2,1),(1,2) ,(3,1)so total 4 .. IMO D..
Updated on: 20 Nov 2018, 05:01
Originally posted by Archit3110 on 20 Nov 2018, 04:33.
Last edited by Archit3110 on 20 Nov 2018, 05:01, edited 1 time in total.
Last edited by Archit3110 on 20 Nov 2018, 05:01, edited 1 time in total.
Kudos
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Archit3110
Bunuel
How many ordered pairs of positive integers (x,y) satisfy the inequality 2x + 3y < 10 ?
A. One
B. Two
C. Three
D. Four
E. Five
A. One
B. Two
C. Three
D. Four
E. Five
2x + 3y < 10 would hold true for values of + ve integers at ( 0,0), (1,1), ( 2,1),(1,2) so total 4 .. IMO D..
