The original number must be a multiple of 14..

14, 28, 42, 56, ....

let's start converting

= \(\frac{1}{14}\)( dropping 4 from 14) = \(\frac{1}{14}\) = solution

= \(\frac{2}{28}\)( dropping 2 from 28) = \(\frac{1}{14}\) = solution

= \(\frac{4}{42}\)( dropping 4 from 42) = \(\frac{2}{21}\) = Not a solution

= \(\frac{5}{56}\)( dropping 5 from 56) = \(\frac{5}{56}\) = Not a solution

so the denominator must be a multiple of numerator which is not possible as we proceed further : hence only 2 solution

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