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Bunuel
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Bunuel
How many three-digit numbers can be formed without using the digits 2, 3, 5, 7 if the repetition of the digits is not allowed?

(A) 216
(B) 180
(C) 162
(D) 156
(E) 125


Restrictions
1) Digits to be used: 0, 1, 4, 6, 8, 9
2) No repetition allowed

Let the number be xyz
Now x can take any value except 0, so 5 ways
y can take any values including 0, but excluding the digit used for x. So 5 ways
z can take remaining 4 values.
Total ways: 5*5*4=100 ways.
The answer is not in choices.

May be the question meant repetitions allowed.
Then x can take 5 values, and both y and z can take 6 values each.
Total: 5*6*6=180

B, but the question should be ‘repetition is allowed.’

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Fixed the typo. Thank you!
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A 3 digit number means we have 3 places to fill , and the first place cannot be 0. Also, repetition is allowed .

Numbers allowed are 0,1,4,6,8,9

First place can have 5 digits
Second place can have 6 digits
Third place can have 6 digits

Therefore, 5*6*6 = 180


Option B
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