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09 Oct 2025, 00:55
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B
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Difficulty:
15%
(low)
Question Stats:
81% (00:40) correct
19%
(00:45)
wrong
based on 153
sessions
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How many two-digit numbers can be formed from the digits 1 through 9, if no digit appears twice in a number?
(A) 36
(B) 72
(C) 81
(D) 144
(E) 162
(A) 36
(B) 72
(C) 81
(D) 144
(E) 162
09 Oct 2025, 02:58
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For the first digit: There are 9 choices (1 through 9, since 0 is not included).
For the second digit: After selecting the first digit, 8 digits remain.
So, the total is: 9×8=72
The correct option is: (B) 72.
For the second digit: After selecting the first digit, 8 digits remain.
So, the total is: 9×8=72
The correct option is: (B) 72.
09 Oct 2025, 06:37
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Bunuel
Using the digits (1 to 9) totally 9 nos.
The number of two digit numbers that can be formed = 9*9 = 81.
81 nos include the numbers which is repeating also.
The repeating numbers are : {11, 22, 33, 44, 55, 66, 77, 88, 99} . That’s 9 numbers.
The number of digits without repetition = 81 - 9 = 72.
Option B
