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How do we arrive at 6!/6? I had chosen the answer for 6! only. What is the logic behind this please?
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ways in which 6 friends can sit around a circular table = (6-1)! = 5! = 120
Correct Answer - D
I wouldn't explain the logic again chetan has done it already very well
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How many ways can six friends be arranged around a circular dinner table?

A. 16
B. 48
C. 96
D. 120
E. 720

Formula to arrange \(n\) distinct objects in circle \(= (n−1)!\)

Number of ways 6 friends can be arranged around a circular dinner table \(= (6 -1)! = 5!\)

\(5! = 5*4*3*2*1 = 120\)

Answer (D)...
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How many ways can six friends be arranged around a circular dinner table?

A. 16
B. 48
C. 96
D. 120
E. 720

Since we are seating 6 people around a circle, the people can be arranged in (6-1)! = 5! = 120 ways.

Answer: D
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How many ways can six friends be arranged around a circular dinner table?

A. 16
B. 48
C. 96
D. 120
E. 720

For a circle the formula departs from the traditional method so instead of 6! the formula is 5! (n-1!)

D
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How many ways can six friends be arranged around a circular dinner table?

A. 16
B. 48
C. 96
D. 120
E. 720

OA:D

Number of ways six friends can be arranged around a circular dinner table \(=\frac{n!}{n}=\frac{6!}{6}=5!=120\)
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portfolio1
How many ways can six friends be arranged around a circular dinner table?

A. 16
B. 48
C. 96
D. 120
E. 720

for any circular combination formulation is always : (n-1)!
so here n = 6
5! = 120
there are 120 ways in which 6 friends can be arranged around a circular table :)
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chetan2u
Anonamy
How do we arrive at 6!/6? I had chosen the answer for 6! only. What is the logic behind this please?


Hi,
in a normal row, say abcdef is the number of chair and mr x is one of the person sitting on these chairs...
in normal scenario/row , the moment x sits on a different chair a,b,c,d,e, or f, it is a new arrangement...
but it is different in case of a circle.. the seating arrangement is continous, there is no edge..
so say 1,2,3,4,5,6 are sitting on a,b,c,d,e,f respectively...
when they shift a sit to the right, the sitting arrangement becomes 6,1,2,3,4,5, which is different from 1,2,3,4,5,6( total 6 such arrangements)...
but in a circle 1,2,3,4,5,6 is same as 6,1,2,3,4,5 is same as 5,6,1,2,3,4.. because you are getting the same arrangement of people even if they have changed their seat because the relative positions have not changed.. that is why we divide by 6
Hope , the logic is clear

Thank you for explaining the logic behind 6!/6.

I am not the type of person who can just "memorize" a formula without understanding the logic behind it.

Hope the GMATClub community can benefit from my takeaway.

I got the wrong answer today, because I used the 6! formula which turns out to be the wrong logic as per your explanation.
Should similar question appears on the exam, I must get this type of question right.
Action item for exam: in a time-pressured situation, BE VERY CLEAR what the question is asking you for. Does it make sense for 6! ? Are you sure you are not double-counting any arrangement ? Draw it out (especially when you are not sure about which formula to use).
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number of ways n people can be arranged in a circular table = \((n-1)!\)

\(6 friends = (6-1)! = 5! = 120\)

Answer is D.
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for n object circular arrangement can be done in (n-1)! ways
so for 6 people circular arrangement can be done in (6-1)! =5! =5×4×3×2=120 ways
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No of ways n person can be arranged in a row is n!
No of ways n person can be arranged in a circle is (n-1)!
So, in this case 5! = 120
portfolio1
How many ways can six friends be arranged around a circular dinner table?

A. 16
B. 48
C. 96
D. 120
E. 720
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