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Your original thread contains two concepts one that includes "neither" where the data doesn't belong to any set in consideration. How would that be solved using the above explanation as given by whiplash? Thanks in advance for your help.

P.S - I have been reviewing both threads and just found the above explanation easier to understand than yours but it doesn't address "neither" as a concept and we know that there is no one better here to explain the concepts on this forum . Much appreciated!
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Re: How to draw a Venn Diagram for problems [#permalink]

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30 Aug 2014, 05:40

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: How to draw a Venn Diagram for problems [#permalink]

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02 Sep 2015, 12:05

Thanks for the post whiplash2411. However, there is an easier and faster way to do this.

Math = 53 Chemistry = 88 English = 58 Total = 199

This total counts x, y, z twice (students taking 2 classes) and 6 thrice (students taking 3 classes). We need to count these only once to arrive at the number of students taking exactly 2 classes.

First get rid of the double counting by subtracting the actual number of students from the total above. Deal with the triple counting in the next step.

Total = 199 No. of students =(150) Remaining = 49

Since 6 has been counted thrice, subtract 6 twice (6*2 = 12) from the remainder to count it exactly once.

Remaining = 49 Subtract 12 =(12) Final = 37

Thus, the number of students taking exactly 2 classes is 37.

Re: How to draw a Venn Diagram for problems [#permalink]

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18 Jun 2017, 03:00

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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