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In your example: The first number divisible by 3 in your set would be -39 and the last would be 99 step 1: subtract largest divisible number in set by the smallest: 99 - (-39) = 138 step 2: divide the difference by the divisible number: 138 / 3 = 46 step 3: add 1: 46 + 1 = 47 total numbers between 99 and -39 that are divisible by 3
This is easy to see with small numbers For example: set = from 7 to 21, we need to find number of numbers divisible by 7 21- 7 = 14 14 / 7 = 2 2 + 1 = 3
In your example: The first number divisible by 3 in your set would be -39 and the last would be 99 step 1: subtract largest divisible number in set by the smallest: 99 - (-39) = 138 step 2: divide the difference by the divisible number: 138 / 3 = 46 step 3: add 1: 46 + 1 = 47 total numbers between 99 and -39 that are divisible by 3
This is easy to see with small numbers For example: set = from 7 to 21, we need to find number of numbers divisible by 7 21- 7 = 14 14 / 7 = 2 2 + 1 = 3
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Yeah its called sequence & series :
Lets say u need to know how many numbers are there between 40 to 100 that are multiple of 3.
So start with first multiple of 3 after 40. In this case it is 42 and the last multiple of 3 before 100. Its 99. So the formula is
nth term = first term + (n-1)*d where d is the difference between each of the consecutive numbers. In this case it is 3 n= number of terms (which is what you are looking for)
So using above formula : nth term is 99 first term is 42 and d is 3
So 99 = 42 + (n-1)*3 57 = (n-1)*3 n-1 = 19 n = 20
You can cross check by any other method ..
This topic is called Sequence and series which we (Indians) study in 11th grade maths...
Hit kudos if this helps!!!
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