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Intern
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Joined: 10 Jun 2018
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How to solve this [#permalink]

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New post 10 Jun 2018, 08:37
if p=101^100 and q=100^101 then correct relation

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Re: How to solve this [#permalink]

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New post 10 Jun 2018, 08:59
Can you provide options
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New post 10 Jun 2018, 10:02
The extra 1 value in the base 101^100 will be insignificant in comparison to the extra two zeros added by the last power in the exponent. Therefore, 100^101 > 101^100
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New post 11 Jun 2018, 10:51
Re: How to solve this   [#permalink] 11 Jun 2018, 10:51
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