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# I am stuck on the following Algebra expression:

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Intern
Joined: 17 May 2007
Posts: 5
Schools: Kellogg Class of 2012
I am stuck on the following Algebra expression: [#permalink]

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01 Sep 2008, 12:32
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I am stuck on the following Algebra expression:

(3x^2(x-2)-x+2)/(x-2)

A) 3x^2-x+2
B) 3x^2+1
C) 3x^2
D) 3x^2-1
E) 3x^2-2

I know the solution is very simple but I am absolutely stuck right now. Can anyone help?
Intern
Joined: 16 Feb 2006
Posts: 30
Location: ZURICH
Re: Paper Test 28 [#permalink]

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01 Sep 2008, 12:48
(3x^2(x-2)-x+2)/(x-2)

A) 3x^2-x+2
B) 3x^2+1
C) 3x^2
D) 3x^2-1
E) 3x^2-2

I think the question is something like

(3x^2(x-2)-x+2)/(x-2)
= ((3x^2*(x-2))/(x-2)) - 1(x-2)/(x-2)
= 3x^2-1

option is D
_________________

TRY N TRY UNTIL U SUCCEED

Director
Joined: 12 Jul 2008
Posts: 513
Schools: Wharton
Re: Paper Test 28 [#permalink]

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01 Sep 2008, 12:49
Moorehn422 wrote:
I am stuck on the following Algebra expression:

(3x^2(x-2)-x+2)/(x-2)

A) 3x^2-x+2
B) 3x^2+1
C) 3x^2
D) 3x^2-1
E) 3x^2-2

I know the solution is very simple but I am absolutely stuck right now. Can anyone help?

D

(3x^2)(x-2) - x + 2 = (3x^2)(x-2) - (x-2)
= (3x^2-1)(x-2)

Therefore,
(3x^2(x-2)-x+2)/(x-2) = (3x^2-1)(x-2)/(x-2)
=3x^2-1
Senior Manager
Joined: 09 Oct 2007
Posts: 460
Re: Paper Test 28 [#permalink]

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01 Sep 2008, 13:01
Moorehn422 wrote:
I am stuck on the following Algebra expression:

(3x^2(x-2)-x+2)/(x-2)

A) 3x^2-x+2
B) 3x^2+1
C) 3x^2
D) 3x^2-1
E) 3x^2-2

I know the solution is very simple but I am absolutely stuck right now. Can anyone help?

Agree on D.
When you get stuck in a problem like this, simply pick an easy number and solve for x. Then find the answer that yields the same result as the stem.
Intern
Joined: 17 May 2007
Posts: 5
Schools: Kellogg Class of 2012
Re: Paper Test 28 [#permalink]

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01 Sep 2008, 15:12
Thanks all. I completely forgot that little trick asdert...appreciate the help!
Re: Paper Test 28   [#permalink] 01 Sep 2008, 15:12
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# I am stuck on the following Algebra expression:

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