|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
29 Aug 2006, 09:20
Kudos
Bookmarks
I got lost in the wording – what do they want in this one?
In the equation b = ka+3, k is a constant. If the possible solutions are in the form (a,b); is (2,3) a solution to the equation?
(1) (1,4) is a solution to the equation: b = ka + 2
(2) (5,3) is a solution to the equation: 3b = ka – 1
A. St. 1 is sufficient
B. St. 2 is sufficient
C....
D...
E....
In the equation b = ka+3, k is a constant. If the possible solutions are in the form (a,b); is (2,3) a solution to the equation?
(1) (1,4) is a solution to the equation: b = ka + 2
(2) (5,3) is a solution to the equation: 3b = ka – 1
A. St. 1 is sufficient
B. St. 2 is sufficient
C....
D...
E....
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
29 Aug 2006, 09:30
Kudos
Bookmarks
saumster
In the equation b = ka+3, k is a constant. If the possible solutions are in the form (a,b); is (2,3) lets try to paraphrase this one
In simple words it means that
if a=2 and b=3 is the
b = ka+3 equation correct
1 st) 4=1k+2---k=2
suff
2 statement
9=5k-1
k=2
suff
(2,3) are not possible solutions
Hence D
29 Aug 2006, 09:37
Kudos
Bookmarks
I agree with (D)
Two things to watch out for:
- My biggest bogeyman - that the answer to a DS can be NO and still be sufficient!
When you solve for k with the given values, you get k = 0.
Both (a) and (b) give you equations which will give you k values since a and b values are specified.
Therefore regardless of WHAT those values are, you can answer the question!
- The second thing to watch out for when you have two equations in two variables are to make sure they are not saying exactly the same thing, i.e. they are not the same equation. However, in this case even that wont dampen the issue, since the answer will still be D - either is sufficient.
MG
Two things to watch out for:
- My biggest bogeyman - that the answer to a DS can be NO and still be sufficient!
When you solve for k with the given values, you get k = 0.
Both (a) and (b) give you equations which will give you k values since a and b values are specified.
Therefore regardless of WHAT those values are, you can answer the question!
- The second thing to watch out for when you have two equations in two variables are to make sure they are not saying exactly the same thing, i.e. they are not the same equation. However, in this case even that wont dampen the issue, since the answer will still be D - either is sufficient.
MG
