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i, j, and k are non-negative integers such that i+j+k=3. If p, q, and

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 6614
GMAT 1: 760 Q51 V42
GPA: 3.82
i, j, and k are non-negative integers such that i+j+k=3. If p, q, and  [#permalink]

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22 Nov 2017, 01:17
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Difficulty:

65% (hard)

Question Stats:

51% (02:02) correct 49% (02:08) wrong based on 72 sessions

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[GMAT math practice question]

$$i, j$$, and $$k$$ are non-negative integers such that $$i+j+k=3$$. If $$p, q$$, and $$r$$ are three fixed, but different, prime numbers, how many different values of $$p^iq^jr^k$$ are possible?

A. 8
B. 9
C. 10
D. 11
E. 12

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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Expert Joined: 02 Aug 2009 Posts: 7098 Re: i, j, and k are non-negative integers such that i+j+k=3. If p, q, and [#permalink] Show Tags 22 Nov 2017, 01:57 MathRevolution wrote: [GMAT math practice question] $$i, j$$, and $$k$$ are non-negative integers such that $$i+j+k=3$$. If $$p, q$$, and $$r$$ are three fixed, but different, prime numbers, how many different values of $$p^iq^jr^k$$ are possible? A. 8 B. 9 C. 10 D. 11 E. 12 Hi... Since I,j,k have a sum of 3, we have to find ways it is possible.. 1) all three are 1..... One way 2) 0,1,2.....…............. 3! Ways=6 ways 3) 0,0,3….……….......... 3!/2!=3 ways Total = 1+6+3=10 C _________________ 1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html GMAT online Tutor Manager Joined: 20 Feb 2017 Posts: 165 Location: India Concentration: Operations, Strategy WE: Engineering (Other) i, j, and k are non-negative integers such that i+j+k=3. If p, q, and [#permalink] Show Tags 22 Nov 2017, 02:58 The question basically asks how many whole number solution is possible here the answer is 5c2 = 10 ways therefore the answer must be 10 DIRECT FORMULA : (n+r-1) C (r-1) here n= 3 and r=3 _________________ If you feel the post helped you then do send me the kudos (damn theya re more valuable than$)

Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 6614
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: i, j, and k are non-negative integers such that i+j+k=3. If p, q, and  [#permalink]

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24 Nov 2017, 00:27
=>

The number of possible values of $$p^iq^jr^k$$ is equal to the number of solutions of the equation $$i + j + k = 3$$.
The solution set of the equation $$i + j + k = 3$$ includes all permutations of $$(3,0,0), (2,1,0), and (1,1,1)$$.
The number of permutations of $$(3,0,0)$$ is $$\frac{3!}{2!} = 3$$.
The number of permutations of $$(2,1,0)$$ is $$3! = 6.$$
The number of permutations of $$(1,1,1)$$ is $$1$$.

Therefore, the number of solutions of the equation $$i+j+k=3$$ is $$3 + 6 + 1 = 10$$.

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Re: i, j, and k are non-negative integers such that i+j+k=3. If p, q, and  [#permalink]

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27 Nov 2017, 11:32
MathRevolution wrote:

$$i, j$$, and $$k$$ are non-negative integers such that $$i+j+k=3$$. If $$p, q$$, and $$r$$ are three fixed, but different, prime numbers, how many different values of $$p^iq^jr^k$$ are possible?

A. 8
B. 9
C. 10
D. 11
E. 12

Let’s first determine the number of non-negative integer triples (i, j, k) we can have:

(0,0,3), (0,3,0), (3,0,0)
(0,1,2), (0,2,1), (1,0,2), (1,2,0), (2,0,1), (2,1,0)
(1,1,1)

We see that there are 10 triples, and when they are assigned as the exponents for p, q and r, we will have 10 different values of p^i * q^j * r^k.

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Re: i, j, and k are non-negative integers such that i+j+k=3. If p, q, and &nbs [#permalink] 27 Nov 2017, 11:32
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