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I run into this problem and have no clue what to do and how [#permalink]

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28 Sep 2008, 16:15

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I run into this problem and have no clue what to do and how to approach it (if you answer please explain the steps)

For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

one two three four five
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For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

one two three four five

The answer is three: (1*-3)=-3 negative (-3*2)=-6 negative (2*5)=10 positive (5*-4)=-20 negative (-4*-6)=24 positive 3 Negative products of consecutive terms

For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

one two three four five

The answer is three: (1*-3)=-3 negative (-3*2)=-6 negative (2*5)=10 positive (5*-4)=-20 negative (-4*-6)=24 positive 3 Negative products of consecutive terms