Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.
May 1408:30 AM PDT
-09:30 AM PDT
Most GMAT test-takers are intimidated by the hardest GMAT Verbal questions. In this session, Target Test Prep GMAT instructor Erika Tyler-John, a 100th percentile GMAT scorer, will show you how top scorers break down challenging Verbal questions..- Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
05 Oct 2005, 20:30
Kudos
Bookmarks
(i) The probability that a certain variety of plant produces a yellow flower is 1/5. If two plants are selected at random, what is the probability that:
(a) both produces yellow flowers
(b) only one produces a yellow flower
(c) there are no yellow flower
(d) at least one produces a yellow flower.
(ii) If n of these plants are selected, what is the probability that there is at least one yellow flower.
(a) both produces yellow flowers
(b) only one produces a yellow flower
(c) there are no yellow flower
(d) at least one produces a yellow flower.
(ii) If n of these plants are selected, what is the probability that there is at least one yellow flower.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
I have to admit probability is my weakest area. So these might be off by miles!
1)
a) Probability of both flowering yellow = probability of plant one flowering yellow*probability of plant two flowering yellow = 1/5*1/5=1/25
b) only one flowering yellow implies the other does not flower yellow. This can happen in 2 ways, ie, 1st yellow, 2nd not yellow. or 1st not yellow and second yellow.
(1/5*4/5)*2=8/25 {after seeing ywilfred's post!}
c) probability of no yellow = 4/5*4/5=16/26
d) probability of atleast 1 yellow = 1-probability of no yellow.
probability of no yellow = 4/5*4/5=16/25.
probability of atleast 1 yellow = 1-16/25=9/25
2)
probability of no yellow flowers = 4/5 per plant.
probability of no flowers for n plants = (4/5)^n
probability of atleast 1 yellow flower = 1-(4/5)^n
what are the OAs?
1)
a) Probability of both flowering yellow = probability of plant one flowering yellow*probability of plant two flowering yellow = 1/5*1/5=1/25
b) only one flowering yellow implies the other does not flower yellow. This can happen in 2 ways, ie, 1st yellow, 2nd not yellow. or 1st not yellow and second yellow.
(1/5*4/5)*2=8/25 {after seeing ywilfred's post!}
c) probability of no yellow = 4/5*4/5=16/26
d) probability of atleast 1 yellow = 1-probability of no yellow.
probability of no yellow = 4/5*4/5=16/25.
probability of atleast 1 yellow = 1-16/25=9/25
2)
probability of no yellow flowers = 4/5 per plant.
probability of no flowers for n plants = (4/5)^n
probability of atleast 1 yellow flower = 1-(4/5)^n
what are the OAs?
05 Oct 2005, 21:29
Kudos
Bookmarks
My probability sucks, but I'll try all the same. 
P(Yellow) = 1/5
P(Not Yellow) = 4/5
(a) Both produces yellow flowers = P(Yellow) AND P(Yellow) = 1/5 x 1/5 = 1/25
(b) Only one produces a yellow flower = P(1st flower yellow) AND P(2nd flower not yellow) OR P(1st flower not yellow) AND P(2nd flower yellow) = 1/5*4/5 + 1/5*4/5 = 4/25 *2 = 8/25
(c) P(No yellow) = 4/5 *4/5 = 16/25
(d) P(at least one yellow) P(only one yellow) OR P(both yellow) = 8/25 + 1/25 = 9/25
P(Yellow) = 1/5
P(Not Yellow) = 4/5
(a) Both produces yellow flowers = P(Yellow) AND P(Yellow) = 1/5 x 1/5 = 1/25
(b) Only one produces a yellow flower = P(1st flower yellow) AND P(2nd flower not yellow) OR P(1st flower not yellow) AND P(2nd flower yellow) = 1/5*4/5 + 1/5*4/5 = 4/25 *2 = 8/25
(c) P(No yellow) = 4/5 *4/5 = 16/25
(d) P(at least one yellow) P(only one yellow) OR P(both yellow) = 8/25 + 1/25 = 9/25
