I12-15

Question

In a school, every student who scores above 90% in the final exam receives a Merit certificate. Last year, exactly 9% of the students received a Merit certificate.
 
In the table, select for  Students with Merit certificates  a value representing the number of students who could have scored above 90% last year, and select for  Total students  a value representing the total number of students in the school that would be jointly consistent with the given information. Make only two selections, one in each column.

Bunuel · Answer

Official Solution:

Essentially, we are looking for a pair of options where the value in the first column is 9% of the value in the second column.
 
Starting with the greatest value:
 
9% of 10,800 is 972. Since 972 is not an option, 10,800 is eliminated.
 
9% of 1,200 is 108. Since 108 is an available option,  Students with Merit certificates  could have been 108, and  Total students  could have been 1,200.

Correct answer:

Students with Merit certificates  "108"

Total students  "1,200"

ankitsethia96 · Answer

Its an easy question, just requires you to do do basic % calculation
3  small  nos. are given: 90,108, 120 (any of them being  Merit students )
3  big  nos. are given: 1080, 1200, 10800 (any of them being  Total students )

Approach 1:  If u start by small nos.- do division i.e. 90/9%= 1000 (wrong as no option found) OR 108/9%= 1200  (correct)  OR 120/9%= 1333.33 (wrong)
  Approach 2:  Alternatively, if u start by big nos.- do multiplication i.e. 1080 x 9%= 97.2 (wrong as no option found) OR 1200 x9%= 108  (correct)  OR 10800 x 9%= 972 (wrong)

In any case, pair of 108 & 1200 is correct.

Bunuel · Answer

I have revised the question, solution, and formatting by adding more details to enhance clarity.

705in11112025 · Answer

I like the solution - it’s helpful. Can be solved within 30-45 secs

EvenCloth · Answer

I like the solution - it’s helpful.

I12-15

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My Rewards

Students with Merit certificates	Total students
		90
		108
		120
		1,080
		1,200
		10,800