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Hello Bunuel

In your solution above, once you calculated the upper and lower limits for x, how did you select the final values of x. I understand the least possible value shall be 948 liters and not 949 liters.

Thanks in Advance!
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Hello Bunuel

In your solution above, once you calculated the upper and lower limits for x, how did you select the final values of x. I understand the least possible value shall be 948 liters and not 949 liters.

Thanks in Advance!
We are given that 948.7 < x < 1264.9, and since x is an integer greater than 948.7, the least possible value is 949, and since x is an integer less than 1264.9, the greatest possible value is 1264.
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I like the solution - it’s helpful.
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If this que is solved like:
301=k20
399=k20
x=301/20.20root10
x=399/20.root10
and taking root10 as 3.16, I am not able to land at the correct ans, could someone explain whats wrong with this approach? Bunuel
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Aishna1034
If this que is solved like:
301=k20
399=k20
x=301/20.20root10
x=399/20.root10
and taking root10 as 3.3, I am not able to land at the correct ans, could someone explain whats wrong with this approach?

Your approach has two problems.

  1. Using 301 and 399 as if they were the endpoints tightens the true bounds. From 300 < 20k < 400 the extreme k are just-above 15 and just-below 20, not 301/20 and 399/20. Your choice shrinks the interval and can exclude valid integers.
  2. You used \(\sqrt{10} \approx 3.3\), which is too large. \(\sqrt{10} \approx 3.16\).

Hope it helps.
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But shouldnt K be an integer value? 301/20=15.05, 399/20=19.95. Here k will be from 16 to 19 anything, inclusive, just exactly what the official says? What values are missing ? Yep even if root 10 is taken as 3.16, then also 2nd part is coming as 1260.84
Bunuel


Your approach has two problems.

  1. Using 301 and 399 as if they were the endpoints tightens the true bounds. From 300 < 20k < 400 the extreme k are just-above 15 and just-below 20, not 301/20 and 399/20. Your choice shrinks the interval and can exclude valid integers.
  2. You used \(\sqrt{10} \approx 3.3\), which is too large. \(\sqrt{10} \approx 3.16\).

Hope it helps.
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Aishna1034
But shouldnt K be an integer value? 301/20=15.05, 399/20=19.95. Here k will be from 16 to 19 anything, inclusive, just exactly what the official says? What values are missing ? Yep even if root 10 is taken as 3.16, then also 2nd part is coming as 1260.84


No, k doesn’t have to be an integer. The question only says the water requirement is proportional to √(weight), so k can be any real number. That’s why the valid range is just above 15 and just below 20, giving x between 949 and 1264. Please check the OE.

Hope it helps.
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