I28-69

Question

A maintenance team estimated that a certain pipe pumped 1,300 liters of water into a storage tank in 4 hours. The volume estimate may be off by up to and including 50 liters, and the time estimate may be off by up to and including 0.5 hours.
 
Select for  Minimum  the lowest possible actual pumping rate (in liters per hour), and select for  Maximum  the highest possible actual pumping rate (in liters per hour), consistent with these estimation ranges. Make only two selections, one in each column.

Bunuel · Answer

Official Solution:

• The actual volume is between 1,250 and 1,350 liters, inclusive.
 
• The actual time is between 3.5 and 4.5 hours, inclusive.
 
For the minimum possible actual pumping rate (in liters/hour), use the lowest volume (numerator) and the highest time (denominator):
 
 \frac{1,250}{4.5}  liters/hour
 
For the maximum possible actual pumping rate (in liters/hour), use the highest volume (numerator) and the lowest time (denominator):
 
 \frac{1,350}{3.5}  liters/hour

Correct answer:

Minimum  " \frac{1,250}{4.5} "

Maximum  " \frac{1,350}{3.5} "

Minimum	Maximum
		\(\frac{1,300}{3}\)
		\(\frac{1,350}{3.5}\)
		\(\frac{1,250}{3.5}\)
		\(\frac{1,350}{4.5}\)
		\(\frac{1,250}{4.5}\)
		\(\frac{1,250}{5}\)

Minimum	Maximum
		\(\frac{1,300}{3}\)
		\(\frac{1,350}{3.5}\)
		\(\frac{1,250}{3.5}\)
		\(\frac{1,350}{4.5}\)
		\(\frac{1,250}{4.5}\)
		\(\frac{1,250}{5}\)

I28-69

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