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13 Jan 2026, 12:44
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Blend Green: 240
Blend Rich: 150
A gardener can prepare two types of dry fertilizer blends by mixing three granular nutrients: Nitrogen (N), Phosphorus (P), and Potassium (K). The gardener's current inventory is 120 grams of N, 90 grams of P, and 60 grams of K.
The gardener may use any amount up to the available inventory, and any unused nutrients may remain.
Blend Green has an N : P : K ratio by weight of 3 : 2 : 1.
Blend Rich has an N : P : K ratio by weight of 2 : 1 : 2.
The gardener will make only one blend, either Blend Green or Blend Rich, using only the nutrients in the inventory.
Select for Blend Green the maximum amount, in grams, of Blend Green that the gardener can prepare, and select for Blend Rich the maximum amount, in grams, of Blend Rich that the gardener can prepare, according to the information provided. Make only two selections, one in each column.
The gardener may use any amount up to the available inventory, and any unused nutrients may remain.
Blend Green has an N : P : K ratio by weight of 3 : 2 : 1.
Blend Rich has an N : P : K ratio by weight of 2 : 1 : 2.
The gardener will make only one blend, either Blend Green or Blend Rich, using only the nutrients in the inventory.
Select for Blend Green the maximum amount, in grams, of Blend Green that the gardener can prepare, and select for Blend Rich the maximum amount, in grams, of Blend Rich that the gardener can prepare, according to the information provided. Make only two selections, one in each column.
| Blend Green | Blend Rich | |
| 120 | ||
| 150 | ||
| 180 | ||
| 240 | ||
| 270 | ||
| 300 |
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Official Answer
Blend Green: 240
Blend Rich: 150
13 Jan 2026, 12:45
Kudos
Bookmarks
Official Solution:
Blend Green (ratio 3 : 2 : 1)
Think of the blend as being made in “sets” of 3 g N, 2 g P, 1 g K. One full set makes 6 grams of Blend Green. How many full sets can each nutrient support?
• Nitrogen: 120 grams available, needs 3 per set, so 120/3 = 40 sets
• Phosphorus: 90 grams available, needs 2 per set, so 90/2 = 45 sets
• Potassium: 60 grams available, needs 1 per set, so 60/1 = 60 sets
The limiter is the smallest number of sets, because once that nutrient is used up you cannot make another complete set while keeping the required ratio. The smallest is 40, so Nitrogen is the limiter.
Maximum Blend Green = 40 sets * 6 grams per set = 240 grams.
Blend Rich (ratio 2 : 1 : 2)
One full set uses 2 g N, 1 g P, 2 g K and makes 5 grams of Blend Rich. Sets supported:
• Nitrogen: 120/2 = 60 sets
• Phosphorus: 90/1 = 90 sets
• Potassium: 60/2 = 30 sets
The smallest is 30, so Potassium is the limiter.
Maximum Blend Rich = 30 sets * 5 grams per set = 150 grams.
Correct answer:
Blend Green "240"
Blend Rich "150"
Bunuel
Blend Green (ratio 3 : 2 : 1)
Think of the blend as being made in “sets” of 3 g N, 2 g P, 1 g K. One full set makes 6 grams of Blend Green. How many full sets can each nutrient support?
• Nitrogen: 120 grams available, needs 3 per set, so 120/3 = 40 sets
• Phosphorus: 90 grams available, needs 2 per set, so 90/2 = 45 sets
• Potassium: 60 grams available, needs 1 per set, so 60/1 = 60 sets
The limiter is the smallest number of sets, because once that nutrient is used up you cannot make another complete set while keeping the required ratio. The smallest is 40, so Nitrogen is the limiter.
Maximum Blend Green = 40 sets * 6 grams per set = 240 grams.
Blend Rich (ratio 2 : 1 : 2)
One full set uses 2 g N, 1 g P, 2 g K and makes 5 grams of Blend Rich. Sets supported:
• Nitrogen: 120/2 = 60 sets
• Phosphorus: 90/1 = 90 sets
• Potassium: 60/2 = 30 sets
The smallest is 30, so Potassium is the limiter.
Maximum Blend Rich = 30 sets * 5 grams per set = 150 grams.
Correct answer:
Blend Green "240"
Blend Rich "150"
