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13 Jan 2026, 12:53
Kudos
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A: 21
B: 17
A museum issued a certain number of annual passes. 15% of the passes were never activated. Of the activated passes, 40% were Family passes and 60% were Individual passes. Among the activated passes, 21/34 of the Family passes and 1/3 of the Individual passes were used fewer than 6 times during the month.
Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.
Select for A and for B the options that complete the statement so that it is most accurate based on the information provided. Make only two selections, one in each column.
Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.
Select for A and for B the options that complete the statement so that it is most accurate based on the information provided. Make only two selections, one in each column.
| A | B | |
| 17 | ||
| 20 | ||
| 21 | ||
| 24 | ||
| 25 | ||
| 28 |
ShowHide Answer
Official Answer
A: 21
B: 17
13 Jan 2026, 12:53
Kudos
Bookmarks
Official Solution:
Take the whole population as 100% of passes.
15% were never activated, so 85% were activated.
Family and used fewer than 6 times:
Of the activated passes, 40% were Family, so Family activated = 0.85 * 0.40 = 34% of all passes.
Of those Family passes, 21/34 were used fewer than 6 times, so 34% * 21/34 = 21%.
So A = 21.
Individual and used fewer than 6 times:
Of the activated passes, 60% were Individual, so Individual activated = 0.85 * 0.60 = 51% of all passes.
Of those Individual passes, 1/3 were used fewer than 6 times, so 51% * 1/3 = 17%.
So B = 17.
Correct answer:
A "21"
B "17"
Bunuel
Take the whole population as 100% of passes.
15% were never activated, so 85% were activated.
Family and used fewer than 6 times:
Of the activated passes, 40% were Family, so Family activated = 0.85 * 0.40 = 34% of all passes.
Of those Family passes, 21/34 were used fewer than 6 times, so 34% * 21/34 = 21%.
So A = 21.
Individual and used fewer than 6 times:
Of the activated passes, 60% were Individual, so Individual activated = 0.85 * 0.60 = 51% of all passes.
Of those Individual passes, 1/3 were used fewer than 6 times, so 51% * 1/3 = 17%.
So B = 17.
Correct answer:
A "21"
B "17"
