Bunuel
If \(\frac{0.018*10^r}{0.0003*10^w}=6*10^7\), then \(r-w=\)?
(A) 6
(B) 7
(C) 8
(D) 9
(E) 15
Useful property: \(\frac{AB}{CD}=\frac{A}{C} \times \frac{B}{D}\)Given: \(\frac{(0.018)(10^r)}{(0.0003)(10^w)}=(6)(10^7)\)
Apply the above property to the left side to get: \(\frac{0.018}{0.0003} \times \frac{10^r}{10^w}=(6)(10^7)\)
Aside: An easy way to evaluate \(\frac{0.018}{0.0003}\) is to first eliminate the decimals by multiplying numerator and denominator by \(10,000\) to get the equivalent fraction \(\frac{180}{3}\), which equals \(60\).
So we now have: \(60 \times \frac{10^r}{10^w}=(6)(10^7)\)
From here, let's divide both sides by \(60\) to get: \(\frac{10^r}{10^w}=\frac{(6)(10^7)}{60}\)
Simplify the right side: \(\frac{10^r}{10^w}=10^6\)
Finally, we can apply the quotient law to the left side to get: \(10^{r-w} = 10^6\)
Since the bases are equal, we can conclude that the exponents are equal to get: \(r-w=6\)
Answer: A