Another method is to substitute values, which can take up some of your time, but will definitely get you there.
Since x is > 0 and x < 1, it has to be a decimal/fraction.
Take a value which is a perfect square, as some options have a root value. Let's take x = 0.25 = \(0.5^2\)
Option 1: \(\frac{1}{\sqrt{0.25}}= \frac{1}{0.5} = 2\)
Option 2: \(\sqrt{0.25} = 0.5\)
Option 3: \(\frac{x}{\sqrt{\pi}}= \frac{0.25}{\frac{22}{7}} = 0.08\)
Option 4: \(0.25^3 = 0.015\)
Option 5: \(0.25^4 = 0.015^2 = 0.000225\)
Option AArun Kumar
Key takeaways after doing this question.(a) Squares, cubes or higher powers of a positive decimal/fraction, is lesser than the fraction. i.e \( x^n < x\)
(b) Square root of a fraction/decimal is larger than the fraction
(c) If n is a positive integer and n is divided by a fraction x, then the result is always greater than n i.e [m]\frac{n}{x}> n