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Bunuel
If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9


total =x
white mice =2*x/8=x/4
grey mice =3*x/9=x/3
w/g=3/4
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Bunuel
If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9


Given,

1/2 of the white mouse = 1 /8 of the total mouse

8/2 of the white mouse = total mouse

4 white mouse = total mouse...............................................1


again,

1 / 3 of the gray mouse = 1 / 9 of the total mouse

3 gray mouse = total mouse.......................................................2

so, 4 white mouse = 3 gray mouse

white mouse / gray mouse = 3/4 = 3:4

Thus the best option is C.
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Bunuel
If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9
Let the total number of mice be \(72\).

So, \(\frac{White \ Mice}{2} = \frac{72}{8}\)

Or, \(White \ Mice = 18\)

Again , \(\frac{Grey \ Mice}{3} = 72*\frac{1}{9}\)

So, \(Grey \ Mice = 24\)

So, THe ratio of white mice to grey mice is \(18 : 24\) = \(3 : 4\), Answer must be (C)
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Hello from the GMAT Club BumpBot!

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