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If 1/2 of the number of white mice in a a certain laboratory is 1/8

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If 1/2 of the number of white mice in a a certain laboratory is 1/8  [#permalink]

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New post 02 Jul 2018, 23:13
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Question Stats:

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If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9

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Re: If 1/2 of the number of white mice in a a certain laboratory is 1/8  [#permalink]

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New post 02 Jul 2018, 23:34
Bunuel wrote:
If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9


Let,
White Mice = W
Gray Mice = G
Total Mice = T

According to Question,

\frac{1}{2} W = \frac{1}{8} T

Therefore,

W = \frac{T}{4} ------- (1)

Also,

According to question,

\frac{1}{3} G = \frac{1}{9} T

Therefore,

G = \frac{T}{3} --------- (2)

Using equation (1) and (2)

\frac{W}{G} = \frac{3}{4}
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Re: If 1/2 of the number of white mice in a a certain laboratory is 1/8  [#permalink]

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New post 03 Jul 2018, 00:39
Ans: C
lets say T is total No. of Mice: so as given
1/2 of W = 1/8 of T;
so W= 1/4 of T

same way: 1/3 of G = 1/9 of T
so G= 1/3 of T

now we need to find W: G = 1/4 T : 1/3 T

= W:G :: 3:4 Ans.

Bunuel wrote:
If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9

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Re: If 1/2 of the number of white mice in a a certain laboratory is 1/8  [#permalink]

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New post 03 Jul 2018, 02:06
Bunuel wrote:
If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9



total =x
white mice =2*x/8=x/4
grey mice =3*x/9=x/3
w/g=3/4
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Re: If 1/2 of the number of white mice in a a certain laboratory is 1/8  [#permalink]

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New post 03 Jul 2018, 02:55
Bunuel wrote:
If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9



Given,

1/2 of the white mouse = 1 /8 of the total mouse

8/2 of the white mouse = total mouse

4 white mouse = total mouse...............................................1


again,

1 / 3 of the gray mouse = 1 / 9 of the total mouse

3 gray mouse = total mouse.......................................................2

so, 4 white mouse = 3 gray mouse

white mouse / gray mouse = 3/4 = 3:4

Thus the best option is C.
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Re: If 1/2 of the number of white mice in a a certain laboratory is 1/8  [#permalink]

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New post 03 Jul 2018, 07:48
Bunuel wrote:
If \(\frac{1}{2}\) of the number of white mice in a certain laboratory is \(\frac{1}{8}\) of the total number of mice, and \(\frac{1}{3}\) of the number of gray mice is \(\frac{1}{9}\) of the total number of mice, then what is the ratio of white mice to gray mice?


A. 16 : 27

B. 2 : 3

C. 3 : 4

D. 4 : 5

E. 8 : 9

Let the total number of mice be \(72\).

So, \(\frac{White \ Mice}{2} = \frac{72}{8}\)

Or, \(White \ Mice = 18\)

Again , \(\frac{Grey \ Mice}{3} = 72*\frac{1}{9}\)

So, \(Grey \ Mice = 24\)

So, THe ratio of white mice to grey mice is \(18 : 24\) = \(3 : 4\), Answer must be (C)
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Re: If 1/2 of the number of white mice in a a certain laboratory is 1/8 &nbs [#permalink] 03 Jul 2018, 07:48
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