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05 Apr 2023, 06:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
72% (01:53) correct
28%
(01:46)
wrong
based on 349
sessions
History
Date
Time
Result
Not Attempted Yet
If \(\frac{1}{x(x-1)}+\frac{1}{x(x+1)}=\frac{1}{(x+1)(x-1)}\), what is the value of \(x\)?
A. 2
B. 3
C. 0
D. 4
E. No solution
A. 2
B. 3
C. 0
D. 4
E. No solution
06 Apr 2023, 08:32
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The final result is that 2=1 which is not possible.
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13 Apr 2023, 00:47
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Bunuel
Solution:
- \(\frac{1}{x(x-1)}+\frac{1}{x(x+1)}=\frac{1}{(x+1)(x-1)}\)
\(⇒\frac{(x+1)+(x-1)}{x(x-1)(x+1)}=\frac{1}{(x+1)(x-1)}\)
\(⇒\frac{2x}{x}=1\)
\(⇒2=1\) (no solution)
Hence the right answer is Option E
