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If (1/x + x)^2 = 16, then 1/x^2 + x^2 =

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Math Expert
Joined: 02 Sep 2009
Posts: 53066
If (1/x + x)^2 = 16, then 1/x^2 + x^2 =  [#permalink]

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17 Oct 2018, 01:32
00:00

Difficulty:

15% (low)

Question Stats:

90% (00:49) correct 10% (03:05) wrong based on 34 sessions

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If $$(\frac{1}{x} + x)^2 = 16$$, then $$\frac{1}{x^2} + x^2 =$$

A. 4
B. 8
C. 14
D. 16
E. 18

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Joined: 15 Feb 2018
Posts: 247
Re: If (1/x + x)^2 = 16, then 1/x^2 + x^2 =  [#permalink]

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17 Oct 2018, 03:37
1
$$(\frac{1}{x}+x)^{2}$$ =16

($$\frac{1}{x}$$+x)($$\frac{1}{x}$$+x) = 16

$$\frac{1}{x^{2}}+2+x^{2}$$=16

$$\frac{1}{x^{2}}+x^{2}$$=14

C
Re: If (1/x + x)^2 = 16, then 1/x^2 + x^2 =   [#permalink] 17 Oct 2018, 03:37
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