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25 Dec 2017, 22:39
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
36% (01:26) correct
64%
(01:11)
wrong
based on 319
sessions
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Time
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Not Attempted Yet
If \(10 \leq x \leq 20\) and \(5 \leq y \leq 10\), and xy is a prime number, what is the least possible value of xy?
(A) 2
(B) 11
(C) 53
(D) 77
(E) Not possible
New Question
(A) 2
(B) 11
(C) 53
(D) 77
(E) Not possible
New Question
Tranquil Focus
Joined: 14 Jun 2017
Last visit: 15 Mar 2020
Posts: 21
Given Kudos: 3
Location: United States
Schools: Kellogg PT '21 (A) Booth PT '21 (M)
GMAT 1: 710 Q48 V38
GPA: 2.8
Updated on: 26 Dec 2017, 01:53
Originally posted by Tranquil Focus on 25 Dec 2017, 23:29.
Last edited by Tranquil Focus on 26 Dec 2017, 01:53, edited 2 times in total.
Last edited by Tranquil Focus on 26 Dec 2017, 01:53, edited 2 times in total.
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chetan2u , I am new to the forums. How can I retain format of algebraic formulae in my posts? Thanks. BTW- I've read a lot of your posts. You're an awesome teacher and your explanations have helped me learn a lot!
Since \(10 <= x <= 20\) and \(5 <= y <= 10\),
50<=xy<=200.
Now xy is a prime number- no way to get 2, no way to get 11 either. We can get 53 by taking y=5.3 and x=10. So least value of xy is 53. Hence C. Please confirm.
Since \(10 <= x <= 20\) and \(5 <= y <= 10\),
50<=xy<=200.
Now xy is a prime number- no way to get 2, no way to get 11 either. We can get 53 by taking y=5.3 and x=10. So least value of xy is 53. Hence C. Please confirm.
General Discussion
25 Dec 2017, 22:59
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Interesting question. I don’t understand how xy can be a prime number as the very fact that the number is formed by multiplying x and y precludes it from being a prime number unless I’m reading the question wrongly.
Sent from my iPhone using GMAT Club Forum
Sent from my iPhone using GMAT Club Forum
