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If 2^(2x+1)*3^(2y-1) = 8^x*27^y, then x + y =

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If 2^(2x+1)*3^(2y-1) = 8^x*27^y, then x + y =  [#permalink]

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New post 04 Nov 2014, 09:56
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

89% (01:31) correct 11% (01:47) wrong based on 103 sessions

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Re: If 2^(2x+1)*3^(2y-1) = 8^x*27^y, then x + y =  [#permalink]

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New post 04 Nov 2014, 10:07
1
Bunuel wrote:

Tough and Tricky questions: Exponents.



If 2^(2x+1)*3^(2y-1) = 8^x*27^y, then x + y =

A. -3
B. -1
C. 0
D. 1
E. 3

Kudos for a correct solution.


Ans : C
Here is my solution.

2^(2x+1)*3^(2y-1) = 8^x*27^y
Here RHS 8^x*27^y= 2^(3x)*3^(3y)

Equating powers on both sides-->
2x+1=3x , thus x=1 and
2y-1=3y giving y=-1

So, x+y=0
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Re: If 2^(2x+1)*3^(2y-1) = 8^x*27^y, then x + y =  [#permalink]

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New post 10 Nov 2014, 00:10
\(2^{2x+1} * 3^{2y-1} = 8^x * 27^y\)

\(2^{2x+1} * 3^{2y-1} = 2^{3x} * 3^{3y}\)

Equating powers of same bases

2x+1 = 3x

x = 1

2y-1 = 3y

y = -1

x+y = 0

Answer = C
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Re: If 2^(2x+1)*3^(2y-1) = 8^x*27^y, then x + y =  [#permalink]

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New post 29 Nov 2019, 10:02
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Re: If 2^(2x+1)*3^(2y-1) = 8^x*27^y, then x + y =   [#permalink] 29 Nov 2019, 10:02
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