If (-2)^(2x) = 16^2, what is the value of x?

Question

If  (-2)^{(2x)} = 16^2 , what is the value of x?

A. -4
B. 4
C. 8
D. 16
E. 32

Lampard42 · Answer

16^2 = 2^8; So 2x=8; X=4 (ignore -2 as the RHS is +ve and -2 to even power will result in +ve)

Archit3110 · Answer

(-2)^{(2x)} = 16^2 
x=4
IMO B 
+ve will be value since raised to even power

CareerGeek · Answer

(-2)^{(2x)} = 16^2   {Since, (-2)^2 = 4} 
-->  4^x = 16^2 
-->  4^x = (4^2)^2 
-->  x = 4

Option B.

ScottTargetTestPrep · Answer

Since (-2)^2 = 4, so the left hand side is 4^x and since 4^2 = 16, the right hand side is (4^2)^2 = 4^4. So we have:

4^x = 4^4

x = 4

Answer: B

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