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Bunuel
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2 raised to 3 is 8 = Square root of N. Therefore N = 64
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Bunuel
If \(2^3 = \sqrt{N}\), what is N ?

(A) 8
(B) 16
(C) 32
(D) 64
(E) 128
\(\sqrt{N}=8\)

Or, \(N = 64\), Answer will be (D)
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\(2^3\) is 8.

\(\sqrt{N} = 8\) means sqrt of N should be 8. Hence, N = 64

Answer D
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