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If (2^a)(3^b)(5^c) = 3,240,000, then what is the least common multiple

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Re: If (2^a)(3^b)(5^c) = 3,240,000, then what is the least common multiple [#permalink]
Prime factorisation of 3240000=2^6 X 3^4 X5^4
A/C, 2^a X 3^b X 5^c = 2^6 X 3^4 X5^4
Therefore, a=6, b=4, c=4
LCM (6,4,4)= 12
Ans.12 (c)
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Re: If (2^a)(3^b)(5^c) = 3,240,000, then what is the least common multiple [#permalink]
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Re: If (2^a)(3^b)(5^c) = 3,240,000, then what is the least common multiple [#permalink]
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