Bunuel wrote:

If 2^k = 3, then 2^(3k+2) =

A. 29

B. 54

C. 81

D. 83

E. 108

Kudos for a correct solution.

Given: \(2^k = 3\)

Expanding the expression we have at hand, we will get the following

\(2^{3k+2} = 2^{3k}*2^2 = (2^k)^3*4 = 3^3*4 = 27*4 = 108\)

Therefore, the value of the expression \(2^{3k+2}\) is

108 (Option A)
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