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Dan
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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 20 Jul 2005, 07:06
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If -2*x>3*y, is x negative?

(1) y>0
(2) 2*x+5*y-20=0



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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 20 Jul 2005, 09:20
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I will go with A

x < (-3/2)y. In order to satisfy this condition, x will be less than zero, when y is greater than zero and x may be less than zero or greater than zero, when y is less than zero.


Statement 1: Since y is greater than 0, x should always be less than zero.
Statement 2: 2x + 5y = 20, substituting x < (-3/2)y in this we get different values for y, and so x can be both positive or negative.
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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 20 Jul 2005, 09:42
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A

if y > 0, then right side of A is positive. For the left side to be greater than the right side, it too needs to be positive, which means x needs to be negative.

B is insufficient.
2*x+5*y-20=0
x can be 0, +ve or -ve and we can find a corresponding value for y to fit in the equation .
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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 20 Jul 2005, 17:07
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another A :wink:

ST1 SINCE y>0
and -2*x>3*y
3Y IS APOSITIVE NUMBER
-2x to be greater than a positive number
x has to be negative -2 *-x will give A POSITIVE NUMBER bigger than this other positive number 3y sufficient yes


st2 TWO variables one equation insufficient
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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 21 Jul 2005, 02:24
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nope... :-D
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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 21 Jul 2005, 07:18
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think it should be D) it is obvious why A is OK,Let's see B) From B) X=(20-5y)/2. When we substitute in the stem then we get that Y>10 or B) by itself is sufficient
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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 21 Jul 2005, 08:08
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it should be D

1) straight forward...

2) we have 2 equations, 2 unkowns...sufficient....

D it is..
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HowManyToGo
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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 21 Jul 2005, 09:07
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Dan
If -2*x>3*y, is x negative?

(1) y>0
(2) 2*x+5*y-20=0
Show more


Picked D.

A) sufficient
B) given 2x + 3y < 0,
consider ,
2*x+5*y-20=0
or 2y - 20 > 0
or y > 10.

HMTG.
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If -2*x>3*y, is x negative? (1) y>0 (2) 2*x+5*y-20=0 21 Jul 2005, 21:01
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D for me

with -2*x>3*y
-> y 0 => alone is sufficient

(2) 2*x+5*y-20=0
plug in y 0

therefore x alone is sufficient



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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