chetan2u wrote:

If \(-2 < {x} \le {\frac{1}{2}}\) and \(7 < {y} \le 10\), what is the least value of \(x^2*y\) possible?

A. \(2\)

B. \(\frac{7}{4}\)

C. \(0\)

D. \(-8\)

E. \(-14\)

From the asked question, we can conclude that whatever be the value of "x", it can't be negative as x has even exponent.

"y" has a positive range. Therefore eliminate (D) & (E) as answer will always be positive or zero.

Least value of x will be "0" as all the other values (negative or positive) will give positive result for x^2 .

Take any value for "y" from the specified range,

Take x = 0 , y = 8

Least value of x^2 * y will always be "0"

(C)

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