Last visit was: 19 Jul 2024, 04:57 It is currently 19 Jul 2024, 04:57
Toolkit
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

# If -2 < x < 1/2 and 7 < y 10, what

SORT BY:
Tags:
Show Tags
Hide Tags
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11475
Own Kudos [?]: 34436 [4]
Given Kudos: 322
Retired Moderator
Joined: 25 Feb 2013
Posts: 893
Own Kudos [?]: 1555 [0]
Given Kudos: 54
Location: India
GPA: 3.82
examPAL Representative
Joined: 07 Dec 2017
Posts: 1048
Own Kudos [?]: 1799 [0]
Given Kudos: 26
e-GMAT Representative
Joined: 04 Jan 2015
Posts: 3711
Own Kudos [?]: 17333 [0]
Given Kudos: 165
Re: If -2 < x < 1/2 and 7 < y 10, what [#permalink]
chetan2u wrote:
If $$-2 < {x} \le {\frac{1}{2}}$$ and $$7 < {y} \le 10$$, what is the least value of $$x^2*y$$ possible?

A. $$2$$
B. $$\frac{7}{4}$$
C. $$0$$
D. $$-8$$
E. $$-14$$

Irrespective of the range of x, the variable x^2 will always non-negative. If we take into consideration the value of x, which is between -2 and 1/2, we can very easily conclude that the least value of x^2 can be 0, when x = 0.

Since we need to find the least value of x^2 * y, we can easily say it has to be zero, since 0 * anything is always 0.

The correct answer is Option C.
VP
Joined: 13 Apr 2013
Status:It's near - I can see.
Posts: 1467
Own Kudos [?]: 1636 [0]
Given Kudos: 1002
Location: India
Concentration: International Business, Operations
GPA: 3.01
WE:Engineering (Real Estate)
If -2 < x < 1/2 and 7 < y 10, what [#permalink]
chetan2u wrote:
If $$-2 < {x} \le {\frac{1}{2}}$$ and $$7 < {y} \le 10$$, what is the least value of $$x^2*y$$ possible?

A. $$2$$
B. $$\frac{7}{4}$$
C. $$0$$
D. $$-8$$
E. $$-14$$

From the asked question, we can conclude that whatever be the value of "x", it can't be negative as x has even exponent.

"y" has a positive range. Therefore eliminate (D) & (E) as answer will always be positive or zero.

Least value of x will be "0" as all the other values (negative or positive) will give positive result for x^2 .

Take any value for "y" from the specified range,

Take x = 0 , y = 8

Least value of x^2 * y will always be "0"

(C)
If -2 < x < 1/2 and 7 < y 10, what [#permalink]
Moderator:
Math Expert
94411 posts