It is currently 23 Jan 2018, 13:55

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If -2 < x < 1/2 and 7 < y 10, what

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Expert Post
Math Expert
User avatar
D
Joined: 02 Aug 2009
Posts: 5545
If -2 < x < 1/2 and 7 < y 10, what [#permalink]

Show Tags

New post 30 Dec 2017, 21:21
Expert's post
1
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

79% (00:52) correct 21% (00:20) wrong based on 28 sessions

HideShow timer Statistics

If \(-2 < {x} \le {\frac{1}{2}}\) and \(7 < {y} \le 10\), what is the least value of \(x^2*y\) possible?

A. \(2\)
B. \(\frac{7}{4}\)
C. \(0\)
D. \(-8\)
E. \(-14\)
[Reveal] Spoiler: OA

_________________

Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html


BANGALORE/-

PS Forum Moderator
avatar
P
Joined: 25 Feb 2013
Posts: 838
Location: India
GPA: 3.82
GMAT ToolKit User Premium Member Reviews Badge CAT Tests
If -2 < x < 1/2 and 7 < y 10, what [#permalink]

Show Tags

New post 30 Dec 2017, 21:28
chetan2u wrote:
If \(-2 < {x} \le {\frac{1}{2}}\) and \(7 < {y} \le 10\), what is the least value of \(x^2*y\) possible?

A. \(2\)
B. \(\frac{7}{4}\)
C. \(0\)
D. \(-8\)
E. \(-14\)


\(x^2\) can be \(0\) or positive only & \(y\) is positive, so negative options are not possible

as we have to minimize \(x^2*y\) (which is either \(0\) or a positive function) so any value closer or equal to \(0\) will be minimum.

as \(-2 < {x} \le {\frac{1}{2}}\), so \(x=0\) will yield the minimum value of \(x^2*y\).

Answer: \(0\)

option C
Expert Post
examPAL Representative
User avatar
B
Joined: 07 Dec 2017
Posts: 122
Re: If -2 < x < 1/2 and 7 < y 10, what [#permalink]

Show Tags

New post 31 Dec 2017, 00:32
chetan2u wrote:
If \(-2 < {x} \le {\frac{1}{2}}\) and \(7 < {y} \le 10\), what is the least value of \(x^2*y\) possible?

A. \(2\)
B. \(\frac{7}{4}\)
C. \(0\)
D. \(-8\)
E. \(-14\)


The complementary approach to the one provided above is to just use the answers (they are right there in front of us!)
This is an Alternative approach.

Let's start with the smallest possible value in the answers: -14.
Trying out different numbers for x and y we'll just SEE that all of our results are positive.
Therefore we can never get to -14 so (E) is elimianted.
Similarly, we can never get to -8 so (D) is elimianted.
The next smallest answer is 0 and we'll get to it if we choose x=0.
Therefore (C) is possible so it must be our answer.
_________________

David
Senior tutor at examPAL
Signup for a free GMAT course
Image
Image

Expert Post
e-GMAT Representative
User avatar
S
Joined: 04 Jan 2015
Posts: 786
Re: If -2 < x < 1/2 and 7 < y 10, what [#permalink]

Show Tags

New post 31 Dec 2017, 08:05
chetan2u wrote:
If \(-2 < {x} \le {\frac{1}{2}}\) and \(7 < {y} \le 10\), what is the least value of \(x^2*y\) possible?

A. \(2\)
B. \(\frac{7}{4}\)
C. \(0\)
D. \(-8\)
E. \(-14\)



Irrespective of the range of x, the variable x^2 will always non-negative. If we take into consideration the value of x, which is between -2 and 1/2, we can very easily conclude that the least value of x^2 can be 0, when x = 0.

Since we need to find the least value of x^2 * y, we can easily say it has to be zero, since 0 * anything is always 0.

The correct answer is Option C.
_________________












| '4 out of Top 5' Instructors on gmatclub | 70 point improvement guarantee | www.e-gmat.com

Senior Manager
Senior Manager
User avatar
G
Joined: 13 Apr 2013
Posts: 259
Location: India
Concentration: International Business, Operations
Schools: ISB '19
GMAT 1: 480 Q38 V22
GPA: 3.01
WE: Engineering (Consulting)
Premium Member CAT Tests
If -2 < x < 1/2 and 7 < y 10, what [#permalink]

Show Tags

New post 31 Dec 2017, 08:49
chetan2u wrote:
If \(-2 < {x} \le {\frac{1}{2}}\) and \(7 < {y} \le 10\), what is the least value of \(x^2*y\) possible?

A. \(2\)
B. \(\frac{7}{4}\)
C. \(0\)
D. \(-8\)
E. \(-14\)



From the asked question, we can conclude that whatever be the value of "x", it can't be negative as x has even exponent.

"y" has a positive range. Therefore eliminate (D) & (E) as answer will always be positive or zero.

Least value of x will be "0" as all the other values (negative or positive) will give positive result for x^2 .

Take any value for "y" from the specified range,

Take x = 0 , y = 8

Least value of x^2 * y will always be "0"

(C)
_________________

"Success is not as glamorous as people tell you. It's a lot of hours spent in the darkness."

If -2 < x < 1/2 and 7 < y 10, what   [#permalink] 31 Dec 2017, 08:49
Display posts from previous: Sort by

If -2 < x < 1/2 and 7 < y 10, what

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.