chetan2u wrote:
If \(-2 < {x} \le {\frac{1}{2}}\) and \(7 < {y} \le 10\), what is the least value of \(x^2*y\) possible?
A. \(2\)
B. \(\frac{7}{4}\)
C. \(0\)
D. \(-8\)
E. \(-14\)
The complementary approach to the one provided above is to just use the answers (they are right there in front of us!)
This is an Alternative approach.
Let's start with the smallest possible value in the answers: -14.
Trying out different numbers for x and y we'll just SEE that all of our results are positive.
Therefore we can never get to -14 so (E) is elimianted.
Similarly, we can never get to -8 so (D) is elimianted.
The next smallest answer is 0 and we'll get to it if we choose x=0.
Therefore (C) is possible so it must be our answer.
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