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If 2a = 3b = 4c = 72, then what is the average (arithmetic mean) of a,

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Joined: 02 Sep 2009
Posts: 58390
If 2a = 3b = 4c = 72, then what is the average (arithmetic mean) of a,  [#permalink]

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New post 19 Feb 2019, 23:56
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

91% (00:59) correct 9% (00:40) wrong based on 11 sessions

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Joined: 13 Oct 2018
Posts: 85
Location: India
GPA: 3.1
WE: Information Technology (Computer Software)
Re: If 2a = 3b = 4c = 72, then what is the average (arithmetic mean) of a,  [#permalink]

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New post 20 Feb 2019, 00:03
1
Answer muat be 26 .

fron the given equation

2a = 72
so a = 36

simiarly for b = 24
and c = 18

average = 36+24+18 / 3 = 26


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Re: If 2a = 3b = 4c = 72, then what is the average (arithmetic mean) of a,  [#permalink]

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New post 20 Feb 2019, 01:55
Bunuel wrote:
If 2a = 3b = 4c = 72, then what is the average (arithmetic mean) of a, b, and c ?

A. 39
B. 26
C. 24
D. 18
E. 9


a=36, b= 24, c= 18
avg= 26
IMO B
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Re: If 2a = 3b = 4c = 72, then what is the average (arithmetic mean) of a,   [#permalink] 20 Feb 2019, 01:55
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If 2a = 3b = 4c = 72, then what is the average (arithmetic mean) of a,

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