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19 Feb 2019, 23:56
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B
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Difficulty:
5%
(low)
Question Stats:
96% (01:02) correct
4%
(00:40)
wrong
based on 28
sessions
History
Date
Time
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Not Attempted Yet
If 2a = 3b = 4c = 72, then what is the average (arithmetic mean) of a, b, and c ?
A. 39
B. 26
C. 24
D. 18
E. 9
A. 39
B. 26
C. 24
D. 18
E. 9
20 Feb 2019, 00:03
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Answer muat be 26 .
fron the given equation
2a = 72
so a = 36
simiarly for b = 24
and c = 18
average = 36+24+18 / 3 = 26
Please award kudos if helpful
Posted from my mobile device
fron the given equation
2a = 72
so a = 36
simiarly for b = 24
and c = 18
average = 36+24+18 / 3 = 26
Please award kudos if helpful
Posted from my mobile device
Archit3110
Major Poster
20 Feb 2019, 01:55
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Bunuel
a=36, b= 24, c= 18
avg= 26
IMO B
