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# If -2x>3y , is x negative ? 1. y> 0 2. 2x+ 5y -20 =0

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Senior Manager
Joined: 08 Jan 2009
Posts: 292
If -2x>3y , is x negative ? 1. y> 0 2. 2x+ 5y -20 =0  [#permalink]

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23 Aug 2009, 00:09
00:00

Difficulty:

(N/A)

Question Stats:

50% (01:32) correct 50% (01:33) wrong based on 17 sessions

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If -2x>3y , is x negative ?

1. y> 0
2. 2x+ 5y -20 =0

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Manager
Joined: 27 May 2009
Posts: 208

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23 Aug 2009, 00:32
If -2x>3y , is x negative ?

1. y> 0
2. 2x+ 5y -20 =0

IMO A:

For -2x>3y if Y is positive the for LHS to be greater it should be positive whihc can only be possible when X would be negative...SUFF

2nd stmt: 2x < - 3y --> in eqn 2x+ 5y =20..... here what could be 2x = -4y, -5y, -6y,-7y and so on.... as 2x < - 3y, so we see that y can be + as well as -ve....NOT SUFF

Let me know if iam correct
Manager
Joined: 14 Aug 2009
Posts: 119

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23 Aug 2009, 02:12
tkarthi4u wrote:
If -2x>3y , is x negative ?

1. y> 0
2. 2x+ 5y -20 =0

for 1). -2x>3y, y>0, so -2x>0, x<0, suf
for 2). -2x>3y, 2x+5y-20=0
so 5y-20=-2x, then 5y-20>3y, we can get 2y>20, y>10
put y>10 back into 2x+ 5y -20 =0, x must be <0
suf

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Manager
Joined: 27 May 2009
Posts: 208

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23 Aug 2009, 03:25
flyingbunny wrote:
tkarthi4u wrote:
If -2x>3y , is x negative ?

1. y> 0
2. 2x+ 5y -20 =0

for 1). -2x>3y, y>0, so -2x>0, x<0, suf
for 2). -2x>3y, 2x+5y-20=0
so 5y-20=-2x, then 5y-20>3y, we can get 2y>20, y>10
put y>10 back into 2x+ 5y -20 =0, x must be <0
suf

Can you cite any reason in my reasoning ...

2nd stmt: 2x < - 3y --> in eqn 2x+ 5y =20..... here what could be 2x = -4y, -5y, -6y,-7y and so on.... as 2x < - 3y, so we see that y can be + as well as -ve....NOT SUFF...

If -4y we take , then y +ve , else y -ve....so X cant be determined... pLs explain
Manager
Joined: 14 Aug 2009
Posts: 119

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23 Aug 2009, 05:46
rohansherry wrote:
flyingbunny wrote:
tkarthi4u wrote:
If -2x>3y , is x negative ?

1. y> 0
2. 2x+ 5y -20 =0

for 1). -2x>3y, y>0, so -2x>0, x<0, suf
for 2). -2x>3y, 2x+5y-20=0
so 5y-20=-2x, then 5y-20>3y, we can get 2y>20, y>10
put y>10 back into 2x+ 5y -20 =0, x must be <0
suf

Can you cite any reason in my reasoning ...

2nd stmt: 2x < - 3y --> in eqn 2x+ 5y =20..... here what could be 2x = -4y, -5y, -6y,-7y and so on.... as 2x < - 3y, so we see that y can be + as well as -ve....NOT SUFF...

If -4y we take , then y +ve , else y -ve....so X cant be determined... pLs explain

don't understand what you wrote.
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Senior Manager
Joined: 08 Jan 2009
Posts: 292

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23 Aug 2009, 07:29
Thanks flyingbunny. i get it.
Intern
Joined: 30 Jun 2009
Posts: 46

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27 Aug 2009, 04:39
I may have done something wrong but I answered C..

1. -2x>3y
x<3/2y

If y=1, then x<3/2 not suff

2. 2x+5y-20 = 0 insuff

Combined :
if Y=1
2x-15=0
suff

Can someone telle me where I am wrong?
Thx
Manager
Joined: 27 May 2009
Posts: 208

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27 Aug 2009, 06:01
defoue wrote:
I may have done something wrong but I answered C..

1. -2x>3y
x<3/2y
If y=1, then x<3/2 not suff

2. 2x+5y-20 = 0 insuff

Combined :
if Y=1
2x-15=0
suff

Can someone telle me where I am wrong?
Thx

See the red part it should be negative
Intern
Joined: 24 Aug 2009
Posts: 9

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27 Aug 2009, 07:55
1
Given -2x > 3y

STMT 1:
y> 0 or y is +ve or 3y is +ve

for -2x to be greater than a +ve number 3y, x has to be -ve.

Suff.

STMT 2:
2x+5y - 20 = 0
or -2x = 5y - 20

replacing the value of -2x in the given inequality

5y - 20 > 3y

or 5y - 3y > 20 or y > 10

So for -2x to be greater than 3*10

-2x > 30 or -x > 15 or x < -15

Suff.

Both Individually are Suff. - D
Senior Manager
Joined: 29 Jul 2009
Posts: 265

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28 Aug 2009, 02:58
rohansherry wrote:
flyingbunny wrote:
tkarthi4u wrote:
If -2x>3y , is x negative ?

1. y> 0
2. 2x+ 5y -20 =0

for 1). -2x>3y, y>0, so -2x>0, x<0, suf
for 2). -2x>3y, 2x+5y-20=0
so 5y-20=-2x, then 5y-20>3y, we can get 2y>20, y>10
put y>10 back into 2x+ 5y -20 =0, x must be <0
suf

Can you cite any reason in my reasoning ...

2nd stmt: 2x < - 3y --> in eqn 2x+ 5y =20..... here what could be 2x = -4y, -5y, -6y,-7y and so on.... as 2x < - 3y, so we see that y can be + as well as -ve....NOT SUFF...

If -4y we take , then y +ve , else y -ve....so X cant be determined... pLs explain

2nd stmt: 2x < - 3y --> in eqn 2x+ 5y =20..... here what could be 2x = -4y, -5y, -6y,-7y

This part is not correct. 2x cannot be -4y,-5y, -6y ....

2x = 20 - 5y that's all we know
Manager
Joined: 28 Jul 2009
Posts: 114
Location: India
Schools: NUS, NTU, SMU, AGSM, Melbourne School of Business

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28 Aug 2009, 03:15
1
flyingbunny wrote:
tkarthi4u wrote:
If -2x>3y , is x negative ?

1. y> 0
2. 2x+ 5y -20 =0

for 1). -2x>3y, y>0, so -2x>0, x<0, suf
for 2). -2x>3y, 2x+5y-20=0
so 5y-20=-2x, then 5y-20>3y, we can get 2y>20, y>10
put y>10 back into 2x+ 5y -20 =0, x must be <0
suf

Love your explaination. I almost solved it except that I could not think of this at all(the one in red). You really need to pay close attention to every detail , eh!
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Manager
Joined: 14 Aug 2009
Posts: 119

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28 Aug 2009, 06:55
bhanushalinikhil wrote:
flyingbunny wrote:
tkarthi4u wrote:
If -2x>3y , is x negative ?

1. y> 0
2. 2x+ 5y -20 =0

for 1). -2x>3y, y>0, so -2x>0, x<0, suf
for 2). -2x>3y, 2x+5y-20=0
so 5y-20=-2x, then 5y-20>3y, we can get 2y>20, y>10
put y>10 back into 2x+ 5y -20 =0, x must be <0
suf

Love your explaination. I almost solved it except that I could not think of this at all(the one in red). You really need to pay close attention to every detail , eh!

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Non-Human User
Joined: 09 Sep 2013
Posts: 9429
Re: If -2x>3y , is x negative ? 1. y> 0 2. 2x+ 5y -20 =0  [#permalink]

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26 Dec 2017, 05:13
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--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: If -2x>3y , is x negative ? 1. y> 0 2. 2x+ 5y -20 =0 &nbs [#permalink] 26 Dec 2017, 05:13
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