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21 Mar 2020, 00:55
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
93% (01:12) correct
7%
(02:37)
wrong
based on 60
sessions
History
Date
Time
Result
Not Attempted Yet
If \(3x + 4y = -8\), and if \(x - 2y = \frac{1}{2},\) then \(x =\)
(A) -12
(B) \(-\frac{7}{5}\)
(C) \(\frac{1}{3}\)
(D) \(\frac{14}{5}\)
(E) 9
(A) -12
(B) \(-\frac{7}{5}\)
(C) \(\frac{1}{3}\)
(D) \(\frac{14}{5}\)
(E) 9
21 Mar 2020, 08:01
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Solution
Given
In this question, we are given that
- • Two equations of x and y: 3x + 4y = -8 and x – 2y = 1/2
To find
We need to determine
- • The value of x
Approach and Working out
If we multiply the 2nd equation by 2, we get 2x – 4y = 1
Adding this with the first equation, we get 3x + 4y + 2x – 4y = -8 + 1
- Or, 5x = -7
Or, x = -7/5
Thus, option B is the correct answer.
Correct Answer: Option B
17 Jul 2020, 22:05
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\(3x + 4y = -8\) --------i
\(x - 2y = \frac{1}{2}\) ---------ii
Multiply ii by 2,
=> 2x - 4y = 1 --------iii
Adding i and iii,
5x = -7
=> x = -7/5
Hence, OA is (B).
\(x - 2y = \frac{1}{2}\) ---------ii
Multiply ii by 2,
=> 2x - 4y = 1 --------iii
Adding i and iii,
5x = -7
=> x = -7/5
Hence, OA is (B).
