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2 raised to any power will not be negative, eliminate A. Also, 2 raised to any power will not be 1/3, eliminate C
Given 4 raised to a power equals 8 raised to that power +1 suggests power is negative, else 4 raised to some power won't be able to catch up to 1 plus some power of 8. This means y is negative, which would mean the result of 2^y will be fractional. Answer is C
Bunuel
If \(4^y = 8^{(y + 1)}\), what is the value of \(2^y\)?

(A) –8
(B) 1/8
(C) 1/3
(D) 1
(E) 8
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