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29 Nov 2018, 00:32
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (01:01) correct
12%
(01:31)
wrong
based on 190
sessions
History
Date
Time
Result
Not Attempted Yet
If \(5^{x^2−2x} = \frac{1}{5}\), what is the value of x ?
A. -1
B. 1
C. 1 + √2
D. 1 − √2
E. 1 + 2√2
A. -1
B. 1
C. 1 + √2
D. 1 − √2
E. 1 + 2√2
29 Nov 2018, 00:44
Kudos
Bookmarks
5^(x^2 − 2x) = 1/5 = 5^(-1)
Hence , x^2 − 2x = -1
or x^2 − 2x + 1 = 0
(x-1)^2=0
x=1
B
KUDOS will do
Hence , x^2 − 2x = -1
or x^2 − 2x + 1 = 0
(x-1)^2=0
x=1
B
KUDOS will do
Archit3110
Major Poster
29 Nov 2018, 03:38
Kudos
Bookmarks
Bunuel
5^{x^2−2x} = \frac{1}{5}[/m]
x^2-2x+1=0
(x-1)(x-1)=0
x=1 IMO B
