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02 Jul 2020, 02:19
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
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Question Stats:
47% (02:04) correct
53%
(02:42)
wrong
based on 109
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If \(\frac{5x^2 + 65x + 60}{x^2 + 10x -24} = \frac{5x+5}{x-2}\), then which of the following could be the values of x?
I. -37
II. -12
III. 2
(A) I only
(B) III only
(C) I and II only
(D) I and III only
(E) I, II, and III
I. -37
II. -12
III. 2
(A) I only
(B) III only
(C) I and II only
(D) I and III only
(E) I, II, and III
02 Jul 2020, 02:29
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\(\frac{5x^2 + 65x + 60}{x^2 + 10x -24} = \frac{5x+5}{x-2}\)
\(\frac{5(x^2 + 13x +12)}{x^2+10x - 24} = \frac{5(x+1)}{x-2}\)
Factorizing Numerator and denominator of LHS
\(\frac{(x+12)(x+1)}{(x+12)(x-2)} = \frac{x+1}{x-2}\)
X cannot be equal to -12 and 2 as it will lead to an indefinite form.
Only possible value of x = -37.
OA, A
\(\frac{5(x^2 + 13x +12)}{x^2+10x - 24} = \frac{5(x+1)}{x-2}\)
Factorizing Numerator and denominator of LHS
\(\frac{(x+12)(x+1)}{(x+12)(x-2)} = \frac{x+1}{x-2}\)
X cannot be equal to -12 and 2 as it will lead to an indefinite form.
Only possible value of x = -37.
OA, A
Bunuel
If \(\frac{5x^2 + 65x + 60}{x^2 + 10x -24} = \frac{5x+5}{x-2}\), then which of the following could be the values of x?
I. -37
II. -12
III. 2
(A) I only
(B) III only
(C) I and II only
(D) I and III only
(E) I, II, and III
I. -37
II. -12
III. 2
(A) I only
(B) III only
(C) I and II only
(D) I and III only
(E) I, II, and III
02 Jul 2020, 03:56
Kudos
Bookmarks
Explanation:
5x^2+65x+60 / x^2 + 10x − 24 = 5x+5 / x−2
5(x^2+13x+12) / x^2 + 10x − 24 = 5 (x+1) / x-2
(x+12)(x+1)/(x+12)(x−2) = (x+1) / (x−2)
means x cannot be -12 or 2 as denominator become zero.
Only Option left is I
IMO-A
5x^2+65x+60 / x^2 + 10x − 24 = 5x+5 / x−2
5(x^2+13x+12) / x^2 + 10x − 24 = 5 (x+1) / x-2
(x+12)(x+1)/(x+12)(x−2) = (x+1) / (x−2)
means x cannot be -12 or 2 as denominator become zero.
Only Option left is I
IMO-A
