chetan2u
mikemcgarry
If \(6^A = 2\), \(6^B = 5\), and \(6^Q = 15\), then express Q in terms of A and/or B.
(A) 3B
(B) B + 3
(C) 5A + B
(D) \(B^2 - 2B\)
(E) B - A + 1For the solution to this, as well as for a set of challenging problems on exponents, see:
Mike

Hi
see if all can be brought to base 6..now we have 2,5,15 and these can be arranged as \(\frac{15}{5}*2=6\)
substitute corresponding values...
\(\frac{15}{5}*2=\frac{6^Q}{6^B}*6^A=6^{Q+A-B}=6^1........Q+A-B=1........Q=B+1-A\)
E
Hi Chetan,
Can you let me know if this strategy is viable? I am not strong at math and rely on a lot of shortcuts to get to correct answers.
For this question I assumed:
A = 0.5
B = ~0.8
Q = ~1.5
Upon plugging these numbers in to the answer key, [E] was the only answer even CLOSE to correct.
Can you let me know if this is a strategy I can continue to employ?
Thanks