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If 6 students have an average (arithmetic mean) score of 88 on an exam

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If 6 students have an average (arithmetic mean) score of 88 on an exam  [#permalink]

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New post 20 Feb 2019, 00:19
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If 6 students have an average (arithmetic mean) score of 88 on an exam, and one of those students scored a 93 on the exam, what is the average score on this exam for the other 5 students?

A. 84
B. 85
C. 86
D. 87
E. 89

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Re: If 6 students have an average (arithmetic mean) score of 88 on an exam  [#permalink]

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New post 20 Feb 2019, 01:27
amswer is 87 .

total score of 6 students = 88*6 = 528

SCORE of one = 93
so score of 5 = 528 - 93 = 435

SO AVERAGE = 435/5 = 87


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Re: If 6 students have an average (arithmetic mean) score of 88 on an exam  [#permalink]

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New post 20 Feb 2019, 01:56
1
Logically without putting pen on paper
This how you go
Each of this 6 students have a score of 88 since that is the average.
Now you realized one student have 93 which is 5 (more) than the average so the other 5 students need to compensate this 5 more with 5 less to retain the average as 88
So there are 5 students compensating with 5(less) each (88) will be one less (88-1) thus Now average of 87.
Ans is D
Hope it helps

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Re: If 6 students have an average (arithmetic mean) score of 88 on an exam   [#permalink] 20 Feb 2019, 01:56
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