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If 6 students, representing 16 2/3% of the class, failed algebra, how

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If 6 students, representing 16 2/3% of the class, failed algebra, how  [#permalink]

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New post 28 Feb 2018, 23:15
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A
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C
D
E

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Question Stats:

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If 6 students, representing 16 2/3% of the class, failed algebra, how  [#permalink]

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New post 28 Feb 2018, 23:24
Bunuel wrote:
If 6 students, representing 16 2/3% of the class, failed algebra, how many students passed the course?

(A) 48

(B) 42

(C) 36

(D) 30

(E) 32



If 6 is \(16\frac{2}{3}\)% = \(\frac{50}{3}\)%, then x -> 100%

Total number of students(x) = \(100*6 = \frac{50x}{3}\) -> x = \(100*6*\frac{3}{50} = 36\)

Therefore, 30 out of 36 students passed the course(Option D)
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If 6 students, representing 16 2/3% of the class, failed algebra, how  [#permalink]

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New post 01 Mar 2018, 19:07
Bunuel wrote:
If 6 students, representing 16 2/3% of the class, failed algebra, how many students passed the course?

(A) 48

(B) 42

(C) 36

(D) 30

(E) 32

Let C = total students

6 = 16 2/3 % of the class
6 = 16 2/3 % C

16 2/3 % C=\(\frac{16\frac{2}{3}}{100}=\frac{\frac{50}{3}}{100}=\frac{50}{300}=\frac{1}{6}C\)

\(6=\frac{1}{6}C\)
\((6*\frac{6}{1}) = C = 36\)


C = 36
6 failed
(36-6) = 30 passed

Answer D
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Re: If 6 students, representing 16 2/3% of the class, failed algebra, how  [#permalink]

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New post 02 Mar 2018, 23:09
Bunuel wrote:
If 6 students, representing 16 2/3% of the class, failed algebra, how many students passed the course?

(A) 48

(B) 42

(C) 36

(D) 30

(E) 32

IMO D
6=16 2/3% x where x is total number of students in class
6=48+2/3*100 x
6=50/3*100 x
6=1*x/6
x=36
failed is 6 then passes is 36-6=30
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Re: If 6 students, representing 16 2/3% of the class, failed algebra, how &nbs [#permalink] 02 Mar 2018, 23:09
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