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# If (7^3/4)^n=7 what is the value of n? (a) 1/3 (B) 2/3 (c)

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If (7^3/4)^n=7 what is the value of n? (a) 1/3 (B) 2/3 (c)  [#permalink]

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09 May 2006, 13:39
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32. If (7^3/4)^n=7 what is the value of n?

(a) 1/3

(B) 2/3

(c) 4/3

(d) 5/3

(e) 6/3

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Andre Crompton
andre.crompton@cit.com
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09 May 2006, 13:45
If (7^3/4)^n=7

implies (7) ^ (3n/4) = 7 ^1

implies 3n/4 =1

n =4/3
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Joined: 30 Mar 2006
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09 May 2006, 13:54
Ok I understand that.

Then what would (8^2/3)^n=64

what would N be in this case?
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Andre Crompton
andre.crompton@cit.com
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09 May 2006, 14:02
Ok I understand that.

Then what would (8^2/3)^n=64

what would N be in this case?

Applying the same logic...

8^2n/3 = 8^2 (64)

2n/3 = 2 so n = 3
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09 May 2006, 19:55
7^(3n/4) = 7^1

3n/4 = 1
n = 4/3
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09 May 2006, 20:44
andrecrompton wrote:
what would (8^2/3)^n=64
what would N be in this case?

(8^2/3)^n=64
[2^(3)(2/3)]^n=64
(2^2)^n=64
(4)^n=4^3
n = 3
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09 May 2006, 20:47
1
andrecrompton wrote:
32. If (7^3/4)^n=7 what is the value of n?
(a) 1/3
(B) 2/3
(c) 4/3
(d) 5/3
(e) 6/3

(7^3/4)^n=7
7^3n/4 = 7
what value of n makes 7^3n/4 = 7^1?
it is 4/3. so n = 4/3

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Re: If (7^3/4)^n=7 what is the value of n? (a) 1/3 (B) 2/3 (c)  [#permalink]

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20 Aug 2018, 17:19
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Re: If (7^3/4)^n=7 what is the value of n? (a) 1/3 (B) 2/3 (c)   [#permalink] 20 Aug 2018, 17:19
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